- Class 6 Maths
- Class 6 Science
- Class 6 Social Science
- Class 6 English
- Class 7 Maths
- Class 7 Science
- Class 7 Social Science
- Class 7 English
- Class 8 Maths
- Class 8 Science
- Class 8 Social Science
- Class 8 English
- Class 9 Maths
- Class 9 Science
- Class 9 Social Science
- Class 9 English
- Class 10 Maths
- Class 10 Science
- Class 10 Social Science
- Class 10 English
- Class 11 Maths
- Class 11 Computer Science (Python)
- Class 11 English
- Class 12 Maths
- Class 12 English
- Class 12 Economics
- Class 12 Accountancy
- Class 12 Physics
- Class 12 Chemistry
- Class 12 Biology
- Class 12 Computer Science (Python)
- Class 12 Physical Education
- GST and Accounting Course
- Excel Course
- Tally Course
- Finance and CMA Data Course
- Payroll Course

## Interesting

- Learn English
- Learn Excel
- Learn Tally
- Learn GST (Goods and Services Tax)
- Learn Accounting and Finance
- GST Tax Invoice Format
- Accounts Tax Practical
- Tally Ledger List
- GSTR 2A - JSON to Excel

Are you in school ? Do you love Teachoo?

We would love to talk to you! Please fill this form so that we can contact you

- Case Based Questions (MCQ)
- NCERT Exemplar - MCQs
- Forming equations and solving
- Questions - Forming equations and solving

## Example 2 - Chapter 12 Class 12 Linear Programming

Last updated at May 29, 2023 by Teachoo

Learn in your speed, with individual attention - Teachoo Maths 1-on-1 Class

Example 2 Solve the following linear programming problem graphically: Minimise Z = 200 x + 500 y subject to the constraints: x + 2y ≥ 10 3x + 4y ≤ 24 x ≥ 0, y ≥ 0 Minimize Z = 200x + 500y Subject to, x + 2y ≥ 10 3x + 4y ≤ 24 x ≥ 0, y ≥ 0 Hence Z is minimum at (4, 3)

## Davneet Singh

Davneet Singh has done his B.Tech from Indian Institute of Technology, Kanpur. He has been teaching from the past 13 years. He provides courses for Maths, Science, Social Science, Physics, Chemistry, Computer Science at Teachoo.

## Hi, it looks like you're using AdBlock :(

Please login to view more pages. it's free :), solve all your doubts with teachoo black.

## Solve the following linear programming problem graphically : Minimise Z = 200 x + 500 y . . . ( 1 ) subject to the constraints: x + 2 y ≥ 10 . . . ( 2 ) 3 x + 4 y ≤ 24 . . . ( 3 ) x ≥ 0 , y ≥ 0 . . . ( 4 ) .

The shaded region in fig is the feasible region a b c determined by the system of constraints ( 2 ) to ( 4 ) , which is bounded. the coordinates of corner points corner point corresponding value of z ( 0 , 5 ) 2500 ( 4 , 3 ) 2300 ← m i n i m u m ( 0 , 6 ) 3000 a , b and c are ( 0 , 5 ) , ( 4 , 3 ) and ( 0 , 6 ) respectively. now we evaluate z = 200 x + 500 y at these points. hence, minimum value of z is 2300 attained at the point ( 4 , 3 ) ..

Solve the following linear programming problem graphically. Minimize Z = 3x+5y Subject to the constraints x + 2 y ≥ 10 , x + y ≥ 6 , 3 x + y ≥ 8 , x ≥ 0 , y ≥ 0. T o m i n i m i z e : z = 3 x + 5 y S u b j e c t t o t h e c o n s t r a i n t s x + 2 y ≥ 10 , x + y ≥ 6 , 3 x + y ≥ 8 , x ≥ 0 , y ≥ 0

Solve the following linear programming problem graphically: Maximise Z = 7 x + 10 y subject to the constraints 4 x + 6 y ≤ 240 6 x + 3 y ≤ 240 x ≥ 10 x ≥ 0 , y ≥ 0

Solve the following Linear Programming Problems graphically: Minimise Z = − 3 x + 4 y subject to x + 2 y ≤ 8 , 3 x + 2 y ≤ 12 , x ≥ 0 , y ≥ 0 .

Solve the following linear programming problem graphically: Maximize: Z = 60 x + 40 y subject to the constraints:

Solve the following Linear Programming problems graphically: 1. Maximize Z = 3 x + 4 y Subject to the constraints : x + y ≤ 4 , x ≥ 0 , y ≥ 0 2. Minimize Z = − 3 x + 4 y subject to x + 2 y ≤ 8 , 3 x + 2 y ≤ 12 , x ≥ 0 , y ≥ 0

## Solve the following linear programming problem graphically: Minimize Z = 200 x + 500 y Subject to the constraints: x + 2 y ≥ 10 3 x + 4 y ≤ 24 x ≥ 0 , y ≥ 0

Minimise z = 200 x + 500 y subject to x + 2 y ≥ 10 , 3 x + 4 y ≤ 24 , x ≥ 0 , y ≥ 0 x + 2 y = 10 x 0 10 y 5 0 3 x + 4 y = 24 x 0 8 y 6 0 corner points value of z = 200 x + 500 y ( 0 , 6 ) 3000 ( 0 , 5 ) 2500 ( 4 , 3 ) 2300 ∴ minimum value of z is 2300 at ( 4 , 3 ) ..

## Solve the following linear programming problem graphically: Minimise Z = 200x + 500y subject to the constraints x + 2y ≥ 10, 3x + 4 y ≤ 24, x ≥ 0, y ≥ 0

∴ CML is the feasible region, which is bounded. The comer points are C(4, 3), M(0, 6), L(0, 5). At C(4, 3), Z = 800 + 1500 = 2300 At M(0, 6), Z = 0 + 3000 = 3000 At L(0, 5), Z = 0 + 2500 = 2500 ∴ minimum value = 2300 at (4, 3).

## Linear Programming

Mathematics part ii.

- Suggest Edit

## Solve the following linear programming problem graphically. Minimize Z = 200x1 + 500x2 subject to the constraints: x1 + 2x2 ≥ 10; 3x1 + 4x2 ≤ 24 and x1 ≥ 0, x2 ≥ 0. - Business Mathematics and Statistics

Solve the following linear programming problem graphically.

Minimize Z = 200x 1 + 500x 2 subject to the constraints: x 1 + 2x 2 ≥ 10; 3x 1 + 4x 2 ≤ 24 and x 1 ≥ 0, x 2 ≥ 0.

## Solution Show Solution

Since the decision variables, x 1 and x 2 are non-negative, the solution lies in the I quadrant of the plane.

Consider the equations

x 1 + 2x 2 = 10

3x 1 + 4x 2 = 24

The feasible region is ABC and its co-ordinates are A(0, 5) C(0, 6) and B is the point of intersection of the lines

x 1 + 2x 2 = 10 ..........(1)

3x 1 + 4x 2 = 24 .........(2)

Verification of B:

3x 1 + 6x 2 = 30 ..........[(1) × 3] 3x 1 + 4x 2 = 24 .........(2) − − − 2x 2 = 6

From (1), x 1 + 6 = 10

∴ B is (4, 3)

Minimum value occurs at B(4, 3)

∴ The solution is x 1 = 4, x 2 = 3 and Z min = 2300.

- Maharashtra Board Question Bank with Solutions (Official)
- Balbharati Solutions (Maharashtra)
- Samacheer Kalvi Solutions (Tamil Nadu)
- NCERT Solutions
- RD Sharma Solutions
- RD Sharma Class 10 Solutions
- RD Sharma Class 9 Solutions
- Lakhmir Singh Solutions
- TS Grewal Solutions
- ICSE Class 10 Solutions
- Selina ICSE Concise Solutions
- Frank ICSE Solutions
- ML Aggarwal Solutions
- NCERT Solutions for Class 12 Maths
- NCERT Solutions for Class 12 Physics
- NCERT Solutions for Class 12 Chemistry
- NCERT Solutions for Class 12 Biology
- NCERT Solutions for Class 11 Maths
- NCERT Solutions for Class 11 Physics
- NCERT Solutions for Class 11 Chemistry
- NCERT Solutions for Class 11 Biology
- NCERT Solutions for Class 10 Maths
- NCERT Solutions for Class 10 Science
- NCERT Solutions for Class 9 Maths
- NCERT Solutions for Class 9 Science
- CBSE Study Material
- Maharashtra State Board Study Material
- Tamil Nadu State Board Study Material
- CISCE ICSE / ISC Study Material
- Mumbai University Engineering Study Material
- CBSE Previous Year Question Paper With Solution for Class 12 Arts
- CBSE Previous Year Question Paper With Solution for Class 12 Commerce
- CBSE Previous Year Question Paper With Solution for Class 12 Science
- CBSE Previous Year Question Paper With Solution for Class 10
- Maharashtra State Board Previous Year Question Paper With Solution for Class 12 Arts
- Maharashtra State Board Previous Year Question Paper With Solution for Class 12 Commerce
- Maharashtra State Board Previous Year Question Paper With Solution for Class 12 Science
- Maharashtra State Board Previous Year Question Paper With Solution for Class 10
- CISCE ICSE / ISC Board Previous Year Question Paper With Solution for Class 12 Arts
- CISCE ICSE / ISC Board Previous Year Question Paper With Solution for Class 12 Commerce
- CISCE ICSE / ISC Board Previous Year Question Paper With Solution for Class 12 Science
- CISCE ICSE / ISC Board Previous Year Question Paper With Solution for Class 10
- Entrance Exams
- Video Tutorials
- Question Papers
- Question Bank Solutions
- Question Search (beta)
- More Quick Links
- Privacy Policy
- Terms and Conditions
- Shaalaa App
- Ad-free Subscriptions

## Select a course

- Class 1 - 4
- Class 5 - 8
- Class 9 - 10
- Class 11 - 12
- Search by Text or Image
- Textbook Solutions
- Study Material
- Remove All Ads
- Change mode

## IMAGES

## VIDEO

## COMMENTS

Advantages of linear programming include that it can be used to analyze all different areas of life, it is a good solution for complex problems, it allows for better solution, it unifies disparate areas and it is flexible.

Real world uses for linear functions include solving problems and finding unknowns in engineering, economics and finances. A linear function describes a gradual rate of change, either positive or negative. When drawn, it presents a straight...

In geography, a linear scale is a bar or line graphic that shows the distance on the map that is equal to a real-world distance, such as 100 miles. Linear scales are also called bar scales or graphical scales.

Example 2 Solve the following linear programming problem graphically: Minimise Z = 200 x + 500 y subject to the constraints: x + 2y ≥ 10 3x

Click here:point_up_2:to get an answer to your question :writing_hand:solve the following linear programming problem graphically minimise z

Solve the following linear programming problem graphically:Minimize Z=200x+500ySubject to the constraints:x+2y≥ 103x+4y≤ 24x≥ 0,y≥ 0.

Solve the following linear programming problem graphically : Minimize Z = 200x + 500y subject to constraints x + 2y le 10, 3x + 4y le 24, x ge 0, y ge 0.

Solve the following linear programming problem graphically: Minimise Z=200x+500y……………1 subject to the constraints: x+2yge10……………2 3x+4yle24……………3 xge.

Question: 3.2 [6] Solve the following linear programming graphically Minimize: z = 200x + 500y Subject to the constraints: x + 2y 10 3x + 4y

Concept: Mathematical Formulation of Linear Programming Problem. Report Error Is there an error in this question or solution? Download the

Solve the following linear programming problem graphically:Maximize Z = 4x + y Subject to constraint. Mathematics Untold•5.4K views · 23:41. Go

Solve the following LPP graphically minimize Z= 200x +500y s t c x + 2y ≥ 10, 3x+4y ≤ 24, x ≥ 0, y ≥0 - Maths - Linear Programming.

Solve the following linear programming problem graphically: Minimise Z = 200x + 500y subject to the constraints x + 2y ≥ 10, 3x + 4 y ≤ 24, x

Solve the following linear programming problem graphically. Minimize Z = 200x1 + 500x2 subject to the constraints: x1 + 2x2 ≥ 10;