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How to Solve an Algebraic Expression

Last Updated: April 6, 2024 Fact Checked

This article was co-authored by David Jia . David Jia is an Academic Tutor and the Founder of LA Math Tutoring, a private tutoring company based in Los Angeles, California. With over 10 years of teaching experience, David works with students of all ages and grades in various subjects, as well as college admissions counseling and test preparation for the SAT, ACT, ISEE, and more. After attaining a perfect 800 math score and a 690 English score on the SAT, David was awarded the Dickinson Scholarship from the University of Miami, where he graduated with a Bachelor’s degree in Business Administration. Additionally, David has worked as an instructor for online videos for textbook companies such as Larson Texts, Big Ideas Learning, and Big Ideas Math. There are 10 references cited in this article, which can be found at the bottom of the page. This article has been fact-checked, ensuring the accuracy of any cited facts and confirming the authority of its sources. This article has been viewed 490,858 times.

An algebraic expression is a mathematical phrase that contains numbers and/or variables. Though it cannot be solved because it does not contain an equals sign (=), it can be simplified. You can, however, solve algebraic equations , which contain algebraic expressions separated by an equals sign. If you want to know how to master this mathematical concept, then see Step 1 to get started.

Understanding the Basics

Step 1 Understand the difference between an algebraic expression and an algebraic equation.

  • Algebraic expression : 4x + 2
  • Algebraic equation : 4x + 2 = 100

Step 2 Know how to combine like terms.

  • 3x 2 + 5 + 4x 3 - x 2 + 2x 3 + 9 =
  • 3x 2 - x 2 + 4x 3 + 2x 3 + 5 + 9 =
  • 2x 2 + 6x 3 + 14

Step 3 Know how to factor a number.

  • You can see that each coefficient can be divisible by 3. Just "factor out" the number 3 by dividing each term by 3 to get your simplified equation.
  • 3x/3 + 15/3 = 9x/3 + 30/3 =
  • x + 5 = 3x + 10

Step 4 Know the order of operations.

  • (3 + 5) 2 x 10 + 4
  • First, follow P, the operation in the parentheses:
  • = (8) 2 x 10 + 4
  • Then, follow E, the operation of the exponent:
  • = 64 x 10 + 4
  • Next, do multiplication:
  • And last, do addition:

Step 5 Learn how to isolate a variable.

  • 5x + 15 = 65 =
  • 5x/5 + 15/5 = 65/5 =
  • x + 3 = 13 =

Joseph Meyer

Joseph Meyer

To solve an equation for a variable like "x," you need to manipulate the equation to isolate x. Use techniques like the distributive property, combining like terms, factoring, adding or subtracting the same number, and multiplying or dividing by the same non-zero number to isolate "x" and find the answer.

Solve an Algebraic Equation

Step 1 Solve a basic linear algebraic equation.

  • 4x + 16 = 25 -3x =
  • 4x = 25 -16 - 3x
  • 4x + 3x = 25 -16 =
  • 7x/7 = 9/7 =

Step 2 Solve an algebraic equation with exponents.

  • First, subtract 12 from both sides.
  • 2x 2 + 12 -12 = 44 -12 =
  • Next, divide both sides by 2.
  • 2x 2 /2 = 32/2 =
  • Solve by taking the square root of both sides, since that will turn x 2 into x.
  • √x 2 = √16 =
  • State both answers:x = 4, -4

Step 3 Solve an algebraic expression with fractions.

  • First, cross multiply to get rid of the fraction. You have to multiply the numerator of one fraction by the denominator of the other.
  • (x + 3) x 3 = 2 x 6 =
  • Now, combine like terms. Combine the constant terms, 9 and 12, by subtracting 9 from both sides.
  • 3x + 9 - 9 = 12 - 9 =
  • Isolate the variable, x, by dividing both sides by 3 and you've got your answer.
  • 3x/3 = 3/3 =

Step 4 Solve an algebraic expression with radical signs.

  • First, move everything that isn't under the radical sign to the other side of the equation:
  • √(2x+9) = 5
  • Then, square both sides to remove the radical:
  • (√(2x+9)) 2 = 5 2 =
  • Now, solve the equation as you normally would by combining the constants and isolating the variable:
  • 2x = 25 - 9 =

Step 5 Solve an algebraic expression that contains absolute value.

  • |4x +2| - 6 = 8 =
  • |4x +2| = 8 + 6 =
  • |4x +2| = 14 =
  • 4x + 2 = 14 =
  • Now, solve again by flipping the sign of the term on the other side of the equation after you've isolated the absolute value:
  • 4x + 2 = -14
  • 4x = -14 -2
  • 4x/4 = -16/4 =
  • Now, just state both answers: x = -4, 3

Community Q&A

Donagan

  • The degree of a polynomial is the highest power within the terms. Thanks Helpful 9 Not Helpful 1
  • Once you're done, replace the variable with the answer, and solve the sum to see if it makes sense. If it does, then, congratulations! You just solved an algebraic equation! Thanks Helpful 7 Not Helpful 3
  • To cross-check your answer, visit wolfram-alpha.com. They give the answer and often the two steps. Thanks Helpful 8 Not Helpful 5

how to solve algebraic equations with i

You Might Also Like

Evaluate an Algebraic Expression

  • ↑ https://www.math4texas.org/Page/527
  • ↑ https://www.khanacademy.org/math/cc-sixth-grade-math/cc-6th-expressions-and-variables/cc-6th-combining-like-terms/v/combining-like-terms-2
  • ↑ https://www.mathsisfun.com/algebra/factoring.html
  • ↑ https://www.mathsisfun.com/operation-order-pemdas.html
  • ↑ https://sciencing.com/tips-for-solving-algebraic-equations-13712207.html
  • ↑ https://www.mathsisfun.com/algebra/equations-solving.html
  • ↑ https://tutorial.math.lamar.edu/Classes/Alg/SolveExpEqns.aspx
  • ↑ https://www.mathsisfun.com/algebra/fractions-algebra.html
  • ↑ https://math.libretexts.org/Courses/Coastline_College/Math_C045%3A_Beginning_and_Intermediate_Algebra_(Chau_Duc_Tran)/10%3A_Roots_and_Radicals/10.07%3A_Solve_Radical_Equations
  • ↑ https://www.mathplanet.com/education/algebra-1/linear-inequalitites/solving-absolute-value-equations-and-inequalities

About This Article

David Jia

If you want to solve an algebraic expression, first understand that expressions, unlike equations, are mathematical phrase that can contain numbers and/or variables but cannot be solved. For example, 4x + 2 is an expression. To reduce the expression, combine like terms, for example everything with the same variable. After you've done that, factor numbers by finding the lowest common denominator. Then, use the order of operations, which is known by the acronym PEMDAS, to reduce or solve the problem. To learn how to solve algebraic equations, keep scrolling! Did this summary help you? Yes No

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Solving Equations

What is an equation.

An equation says that two things are equal. It will have an equals sign "=" like this:

That equations says:

what is on the left (x − 2)  equals  what is on the right (4)

So an equation is like a statement " this equals that "

What is a Solution?

A Solution is a value we can put in place of a variable (such as x ) that makes the equation true .

Example: x − 2 = 4

When we put 6 in place of x we get:

which is true

So x = 6 is a solution.

How about other values for x ?

  • For x=5 we get "5−2=4" which is not true , so x=5 is not a solution .
  • For x=9 we get "9−2=4" which is not true , so x=9 is not a solution .

In this case x = 6 is the only solution.

You might like to practice solving some animated equations .

More Than One Solution

There can be more than one solution.

Example: (x−3)(x−2) = 0

When x is 3 we get:

(3−3)(3−2) = 0 × 1 = 0

And when x is 2 we get:

(2−3)(2−2) = (−1) × 0 = 0

which is also true

So the solutions are:

x = 3 , or x = 2

When we gather all solutions together it is called a Solution Set

The above solution set is: {2, 3}

Solutions Everywhere!

Some equations are true for all allowed values and are then called Identities

Example: sin(−θ) = −sin(θ) is one of the Trigonometric Identities

Let's try θ = 30°:

sin(−30°) = −0.5 and

−sin(30°) = −0.5

So it is true for θ = 30°

Let's try θ = 90°:

sin(−90°) = −1 and

−sin(90°) = −1

So it is also true for θ = 90°

Is it true for all values of θ ? Try some values for yourself!

How to Solve an Equation

There is no "one perfect way" to solve all equations.

A Useful Goal

But we often get success when our goal is to end up with:

x = something

In other words, we want to move everything except "x" (or whatever name the variable has) over to the right hand side.

Example: Solve 3x−6 = 9

Now we have x = something ,

and a short calculation reveals that x = 5

Like a Puzzle

In fact, solving an equation is just like solving a puzzle. And like puzzles, there are things we can (and cannot) do.

Here are some things we can do:

  • Add or Subtract the same value from both sides
  • Clear out any fractions by Multiplying every term by the bottom parts
  • Divide every term by the same nonzero value
  • Combine Like Terms
  • Expanding (the opposite of factoring) may also help
  • Recognizing a pattern, such as the difference of squares
  • Sometimes we can apply a function to both sides (e.g. square both sides)

Example: Solve √(x/2) = 3

And the more "tricks" and techniques you learn the better you will get.

Special Equations

There are special ways of solving some types of equations. Learn how to ...

  • solve Quadratic Equations
  • solve Radical Equations
  • solve Equations with Sine, Cosine and Tangent

Check Your Solutions

You should always check that your "solution" really is a solution.

How To Check

Take the solution(s) and put them in the original equation to see if they really work.

Example: solve for x:

2x x − 3 + 3 = 6 x − 3     (x≠3)

We have said x≠3 to avoid a division by zero.

Let's multiply through by (x − 3) :

2x + 3(x−3) = 6

Bring the 6 to the left:

2x + 3(x−3) − 6 = 0

Expand and solve:

2x + 3x − 9 − 6 = 0

5x − 15 = 0

5(x − 3) = 0

Which can be solved by having x=3

Let us check x=3 using the original question:

2 × 3 3 − 3 + 3  =   6 3 − 3

Hang On: 3 − 3 = 0 That means dividing by Zero!

And anyway, we said at the top that x≠3 , so ...

x = 3 does not actually work, and so:

There is No Solution!

That was interesting ... we thought we had found a solution, but when we looked back at the question we found it wasn't allowed!

This gives us a moral lesson:

"Solving" only gives us possible solutions, they need to be checked!

  • Note down where an expression is not defined (due to a division by zero, the square root of a negative number, or some other reason)
  • Show all the steps , so it can be checked later (by you or someone else)

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Imaginary Numbers Explained with Formula: $$ \sqrt{-1} \text{= ?} $$

What they are and how to simplify.

$$ i^5 = ? \\ i ^ {21} = ? $$

$$ \sqrt{-25} = ? \\ \sqrt{-18} = ? $$

Video Tutorial on Simplifying Imaginary Numbers

What is an imaginary number anyway?

Imaginary numbers are based on the mathematical number $$ i $$ .

$$ i \text { is defined to be } \sqrt{-1} $$

From this 1 fact, we can derive a general formula for powers of $$ i $$ by looking at some examples.

$ \text{ Table 1} \\ \begin{array}{ccc|c} \hline Expression & & Work & Result \\\hline \red{i^ \textbf{2}} & = & i \cdot i = \sqrt{-1} \cdot \sqrt{-1} & \red{ \textbf{ -1 }} \\\hline \red{i^ \textbf{3}} & = & i^2 \cdot i = -1 \cdot i & \red{ \textbf{-i} } \\\hline \red{ i^ \textbf{4} } & = & i^2 \cdot i^2 -1 \cdot -1 = & \red{1} \\\hline \end{array} $

You should understand Table 1 above .

Table 1 above boils down to the 4 conversions that you can see in Table 2 below. You should memorize Table 2 below because once you start actually solving problems , you'll see you use table 2 over and over again!

Imaginary Number Condensed Table

What is the larger pattern?

In order to understand how to simplify the powers of $$ i $$, let's look at some more examples, and we'll soon see a formula emerge!

$ \begin{array}{c|c|c} Expression & Work & Result \\\hline \red{i^ \textbf{5}} & \blue{i^4} \cdot i^1 = \blue{1} \cdot i & \red{ \textbf{ i }} \\\hline \red{i^ \textbf{6}} & \blue{i^4} \cdot i^2= \blue{1} \cdot -1 & \red{ \textbf{-1}} \\\hline \red{ i^ \textbf{7} } & \blue{ i^4} \cdot i^3 =\blue{1} \cdot -i & \red{ \boldsymbol{ -i}} \\\hline \red{ i^ \textbf{8} } & = \blue{ i^4} \cdot \blue{ i^4}= \blue{1} \cdot \blue{1} = & \red{ \textbf{ 1}} \\\hline \end{array} $

Do you see the pattern yet? Let's look at 4 more and then summarize.

The General Formula

$$ i^k$$ is the same as $$ i^\red{r} $$ where $$ \red{r} $$ is the remainder when k is divided by 4.

Whether the remainder is 1 , 2 , 3 , or 4 , the key to simplifying powers of i is the remainder when the exponent is divided by 4 .

simplifying the powers of the imaginary number i

Practice Problems

$$ i^ {23} $$

Calculate the remainder

$$ 23 \div 4 $$ has a remainder of $$ \red{3} $$

Simplify using Table2

$$ i^{\red{3}} = -i $$

$$ i^ {18} $$

$$ 18 \div 4 $$ has a remainder of $$ \red{2} $$

$$ i^{ \red{2}} $$

$$ i^{ \red{2}} = -1 $$

$$ i^ {41} $$

$$41 \div 4 $$ has a remainder of $$ \red{1} $$

$$ i^{ \red{1}} $$

$$ i^{ \red{1}} = i $$

$$ i^ {100} $$

$$ 100 \div 4 $$ has a remainder of $$ \red{0} $$

$$ i^{ \red{0}} $$

$$ i^{ \red{0}} = 1 $$

$$ 5i^ {22} $$

Remember your order of operations . Exponents must be evaluated before multiplication so you can think of this problem as $$ 5 \cdot (\color{Blue}{i^ {22}}) $$

$$ 22 \div 4 $$ has a remainder of $$ \red{2} $$

Now, the rest

$$ 5 \cdot ( {\color{Blue}-1} ) = -5 $$

$$ 12i^ {36} $$

Remember your order of operations . Exponents must be evaluated before multiplication so you can think of this problem as $$ 12 \cdot ( {\color{Blue}i^ {36}}) $$

$$ 36 \div 4 $$ has a remainder of $$ \red{0} $$

$$ 12 \cdot ( {\color{Blue} 1} ) = 12 $$

$$ 7 i^ {103} $$

Remember your order of operations . Exponents must be evaluated before multiplication so you can think of this problem as $$ 7 \cdot ( {\color{Blue}i^ {103}}) $$

$$ 103 \div 4 $$ has a remainder of $$ \red{3} $$

$$ i^{ \red{3}} $$

$$ i^{ \red{3}} = -i $$

$$ 7 \cdot ( {\color{Blue} -i} ) = -7i $$

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Solve Algebraic Equations

Symbolic Math Toolbox™ offers both symbolic and numeric equation solvers. This topic shows you how to solve an equation symbolically using the symbolic solver solve . To compare symbolic and numeric solvers, see Select Numeric or Symbolic Solver .

Solve an Equation

Return the full solution to an equation, work with the full solution, parameters, and conditions returned by solve, visualize and plot solutions returned by solve, simplify complicated results and improve performance.

If eqn is an equation, solve(eqn, x) solves eqn for the symbolic variable x .

Use the == operator to specify the familiar quadratic equation and solve it using solve .

solx is a symbolic vector containing the two solutions of the quadratic equation. If the input eqn is an expression and not an equation, solve solves the equation eqn == 0 .

To solve for a variable other than x , specify that variable instead. For example, solve eqn for b .

If you do not specify a variable, solve uses symvar to select the variable to solve for. For example, solve(eqn) solves eqn for x .

solve does not automatically return all solutions of an equation. Solve the equation cos(x) == -sin(x) . The solve function returns one of many solutions.

To return all solutions along with the parameters in the solution and the conditions on the solution, set the ReturnConditions option to true . Solve the same equation for the full solution. Provide three output variables: for the solution to x , for the parameters in the solution, and for the conditions on the solution.

solx contains the solution for x , which is pi*k - pi/4 . The param variable specifies the parameter in the solution, which is k . The cond variable specifies the condition in(k, 'integer') on the solution, which means k must be an integer. Thus, solve returns a periodic solution starting at pi/4 which repeats at intervals of pi*k , where k is an integer.

You can use the solutions, parameters, and conditions returned by solve to find solutions within an interval or under additional conditions.

To find values of x in the interval -2*pi<x<2*pi , solve solx for k within that interval under the condition cond . Assume the condition cond using assume .

To find values of x corresponding to these values of k , use subs to substitute for k in solx .

To convert these symbolic values into numeric values for use in numeric calculations, use vpa .

The previous sections used solve to solve the equation cos(x) == -sin(x) . The solution to this equation can be visualized using plotting functions such as fplot and scatter .

Plot both sides of equation cos(x) == -sin(x) .

how to solve algebraic equations with i

Calculate the values of the functions at the values of x , and superimpose the solutions as points using scatter .

( - 0.70710678118654752440084436210485 0.70710678118654752440084436210485 - 0.70710678118654752440084436210485 0.70710678118654752440084436210485 )

how to solve algebraic equations with i

As expected, the solutions appear at the intersection of the two plots.

If results look complicated, solve is stuck, or if you want to improve performance, see, Troubleshoot Equation Solutions from solve Function .

Related Topics

  • Solve System of Linear Equations
  • Solve Differential Equation
  • Solve Differential Algebraic Equations (DAEs)

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Solution - Linear equations with one unknown

Other Ways to Solve

  • Alternative approach

Video Explanation

  • Watch a video of the solution to (4x/9)-25=-x/4

Step-by-step explanation

1. group all x terms on the left side of the equation.

4 x 9 - 25 = - x 4

Add 1 4 x to both sides:

( 4 x 9 - 25 ) + 1 4 · x = ( - x 4 ) + 1 4 x

Group like terms:

( 4 x 9 + 1 4 · x ) - 25 = ( - x 4 ) + 1 4 x

Group the coefficients:

( 4 9 + 1 4 ) x - 25 = ( - x 4 ) + 1 4 x

Find the lowest common denominator:

( ( 4 · 4 ) ( 9 · 4 ) + ( 1 · 9 ) ( 4 · 9 ) ) x - 25 = ( - x 4 ) + 1 4 x

Multiply the denominators:

( ( 4 · 4 ) 36 + ( 1 · 9 ) 36 ) x - 25 = ( - x 4 ) + 1 4 x

Multiply the numerators:

( 16 36 + 9 36 ) x - 25 = ( - x 4 ) + 1 4 x

Combine the fractions:

( 16 + 9 ) 36 · x - 25 = ( - x 4 ) + 1 4 x

Combine the numerators:

25 36 · x - 25 = ( - x 4 ) + 1 4 x

25 36 · x - 25 = ( - 1 + 1 ) 4 x

25 36 · x - 25 = 0 4 x

Reduce the zero numerator:

25 36 x - 25 = 0 x

Simplify the arithmetic:

25 36 x - 25 = 0

2. Group all constants on the right side of the equation

Add 25 to both sides:

( 25 36 x - 25 ) + 25 = 0 + 25

25 36 x = 0 + 25

25 36 x = 25

3. Isolate the x

Multiply both sides by inverse fraction 36 25 :

( 25 36 x ) · 36 25 = 25 · 36 25

( 25 36 · 36 25 ) x = 25 · 36 25

Multiply the coefficients:

( 25 · 36 ) ( 36 · 25 ) x = 25 · 36 25

Simplify the fraction:

x = 25 · 36 25

Multiply the fraction(s):

x = ( 25 · 36 ) 25

How did we do?

Why learn this

Linear equations cannot tell you the future, but they can give you a good idea of what to expect so you can plan ahead. How long will it take you to fill your swimming pool? How much money will you earn during summer break? What are the quantities you need for your favorite recipe to make enough for all your friends? Linear equations explain some of the relationships between what we know and what we want to know and can help us solve a wide range of problems we might encounter in our everyday lives.

Terms and topics

  • Linear equations with one unknown

Related links

  • Linear Equations - Math is fun
  • Solving equations &amp; inequalities | Khan Academy
  • Linear Equations in the Real World | MyWhyU (youtube)

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    First, move everything that isn't under the radical sign to the other side of the equation: √ (2x+9) = 5. Then, square both sides to remove the radical: (√ (2x+9)) 2 = 5 2 =. 2x + 9 = 25. Now, solve the equation as you normally would by combining the constants and isolating the variable: 2x = 25 - 9 =. 2x = 16.

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    Next we can simplify 18 using what we already know about simplifying radicals. The work is shown below. − 18 = i 18 For a > 0 , − a = i a = i ⋅ 9 ⋅ 2 9 is a perfect square factor of 18 = i 9 ⋅ 2 a b = a ⋅ b when a, b ≥ 0 = i ⋅ 3 ⋅ 2 9 = 3 = 3 i 2 Multiplication is commutative. So it follows that − 18 = 3 i 2 .

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    Imaginary numbers are based on the mathematical number i i. i is defined to be −1−−−√ i is defined to be − 1. From this 1 fact, we can derive a general formula for powers of i i by looking at some examples. Table 1. Table 1 Expression i2 i3 i4 = = = Work i ⋅ i = −1−−−√ ⋅ −1−−−√ i2 ⋅ i = −1 ⋅ i i2 ⋅ i2 ...

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  20. Solve Algebraic Equations

    The solve function returns one of many solutions. syms x. solx = solve(cos(x) == -sin(x), x) solx =. -pi/4. To return all solutions along with the parameters in the solution and the conditions on the solution, set the ReturnConditions option to true. Solve the same equation for the full solution.

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  22. (4x/9)-25=-x/4

    Solve linear equation with one unknown (4x/9)-25=-x/4: Tiger Algebra not only solves linear equations with one unknown (4x/9)-25=-x/4, but its clear, step-by-step explanation of the solution helps to better understand and remember the method

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