how to solve distance word problems in algebra

We can use the distance = rate ⋅ time formula to find the distance Lee traveled. d = rt. The formula d = rt looks like this when we plug in the numbers from the problem. The unknown distance is represented with the variable d. d = 65 ⋅ 2.5. To find d, all we have to do is multiply 65 and 2.5. 65 ⋅ 2.5 equals 162.5.

2nd part distance: 115 (5 − t) I can add these two partial-distance expressions, and set them equal to the known total distance: 105 t + 115 (5 − t) = 555. This is an equation in one variable, which I can solve: 105 t + 115 (5 − t) = 555. 105 t + 575 − 115 t = 555. 575 − 10 t = 555. 20 = 10 t.

http://www.emathacademy.com/This video shows how to set up and solve distance rate time word problems for Algebra 1 and Algebra 2. To solve distance rate ti...

Step 1: Draw a diagram to represent the relationship between the distances involved in the problem. Step 2: Set up a chart based on the formula: rate × time = distance. Step 3: Use the chart to set up one or more equations. Step 4: Solve the equations. We will look at three types of Motion Word Problems: Two objects going in opposite directions.

Step 4: Since the total distance is 210, we get the equation: 50t + 55t = 210 105t = 210 Isolate variable t. Answer: They will be 210 miles apart in 2 hours. Example of a distance word problem with vehicles moving in opposite directions. In this video, you will learn to solve introductory distance or motion word problems - for example, cars traveling in opposite directions, bikers traveling ...

Distance problems are word problems that involve the distance an object will travel at a certain average rate for a given period of time. The formula for distance problems is: distance = rate × time or. d = r × t. Things to watch out for: Make sure that you change the units when necessary. For example, if the rate is given in miles per hour ...

Distance, rate and time problems are a standard application of linear equations. When solving these problems, use the relationship rate (speed or velocity) times time equals distance. r⋅t = d r ⋅ t = d. For example, suppose a person were to travel 30 km/h for 4 h. To find the total distance, multiply rate times time or (30km/h) (4h) = 120 km.

How do you solve those crazy distance word problems? Where do you start when it's two cars traveling opposite directions at different rates or speed? Or how ...

Solving algebraic word problems requires us to combine our ability to create equations and solve them. To solve an algebraic word problem: Define a variable. Write an equation using the variable. Solve the equation. If the variable is not the answer to the word problem, use the variable to calculate the answer.

And with that, we have an equation! 80x + 40x = 600. From here, we can use algebra to solve it. By simplifying the left side, we get 120x=600, and then we can divide both sides by 120 to get x = 5 hours. Thankfully, most word problems won't be as tricky as this one, but the principles to solve them will be the same for any distance/rate/time ...

Problem 3:Find the distance between the points on the XY-plane. Round your answer to one decimal place. Answer. [latex]\color{black}8.6[/latex] units. Problem 4:Determine the distance between points on the coordinate plane. Round your answer to two decimal places. Answer. [latex]\color{black}8.06[/latex] units.

Click to see solution. Problem 17. A biker covered half the distance between two towns in 2 hr 30 min. After that he increased his speed by 2 km/hr. He covered the second half of the distance in 2 hr 20 min. Find the distance between the two towns and the initial speed of the biker. Click to see solution. Problem 18.

Now, we substitute the values into the Distance Formula then simplify to get the distance between the two points in question. Example 2: Find the distance between the two points (-3, 2) and (3, 5). Label the parts of each point properly and substitute it into the distance formula.

In this lesson simple typical word problems on Travel and Distance are presented to show the approach and the methodology of their solutions. Problem 1. Two objects moving toward each other. Two cars entered an Interstate highway at the same time and traveled toward each other. (see Figure 1 ). The initial distance between the cars was 390 miles.

There are 10 sets of 100 grams in 1000grams. 100g + 100g+ 100g + 100g + 100g + 100g + 100g+ 100g + 100g + 100g = Total Cost of sunflower seeds. Convert the 100 grams to 70 cents each. You'l get 10 sets of 70 cents. Instead of trying to add all ten up, multiply 10 by 70. Equals 700 cents.

Thanks to all of you who support me on Patreon. You da real mvps! $1 per month helps!! :) https://www.patreon.com/patrickjmt !! Algebra Word Problem: Dist...

Distance, Rate, and Time. For an object moving at a uniform (constant) rate, the distance traveled, the elapsed time, and the rate are related by the formula. d= rt d = r t. where d = d = distance, r = r = rate, and t= t = time. Notice that the units we used above for the rate were miles per hour, which we can write as a ratio miles hour m i l ...

Distance problems are word problems that involve the distance an object will travel at a certain average rate for a given period of time. The formula for distance problems is: distance = rate × time or. d = r × t. Things to watch out for: Make sure that you change the units when necessary. For example, if the rate is given in miles per hour ...

Answer. The motorboat speed in still water is equal to 10 miles per hour. The current speed is 2 miles per hour. Problem 2. Airplane flying into the wind and with the wind. When an airplane flies into the wind, it can travel 3000 miles in 6 hours. When it flies with the wind, it can travel the same distance in 5 hours.

Distance, Rate, Time Word Problems. Examples: An object is in uniform motion when it moves without changing its speed, or rate. The examples illustrate three types of problems involving uniform motion. Each is solved by using a chart, a sketch, and the distance formula. Lea left home and drove toward the ferry office at an average speed of 22 km/h.

Middle School Math Solutions - Inequalities Calculator Next up in our Getting Started maths solutions series is help with another middle school algebra topic - solving... Enter a problem

Rate is distance per time, so its units could be mph, meters per second, or inches per year. Now you can solve the system of equations: 50t = 100 (t - 2) (Multiply both values inside the parentheses by 100.) 50t = 100t - 200. 200 = 50t (Divide 200 by 50 to solve for t.) t = 4. Substitute t = 4 into train No. 1.

Math Word Problem Solutions. Math word problems require interpreting what is being asked and simplifying that into a basic math equation. Once you have the equation you can then enter that into the problem solver as a basic math or algebra question to be correctly solved. Below are math word problem examples and their simplified forms. Word ...

Step 1: Translate the problem into equations with variables. First, we need to translate the word problem into equation (s) with variables. Then, we need to solve the equation (s) to find the solution (s) to the word problems. Translating words to equations. How to recognize some common types of algebra word problems and how to solve them step ...