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## Unit 2: Solving equations & inequalities

• Why we do the same thing to both sides: Variable on both sides (Opens a modal)
• Intro to equations with variables on both sides (Opens a modal)
• Equations with variables on both sides: 20-7x=6x-6 (Opens a modal)
• Equation with variables on both sides: fractions (Opens a modal)
• Equation with the variable in the denominator (Opens a modal)
• Equations with variables on both sides Get 3 of 4 questions to level up!
• Equations with variables on both sides: decimals & fractions Get 3 of 4 questions to level up!

## Linear equations with parentheses

• Equations with parentheses (Opens a modal)
• Reasoning with linear equations (Opens a modal)
• Multi-step equations review (Opens a modal)
• Equations with parentheses Get 3 of 4 questions to level up!
• Equations with parentheses: decimals & fractions Get 3 of 4 questions to level up!
• Reasoning with linear equations Get 3 of 4 questions to level up!

## Analyzing the number of solutions to linear equations

• Number of solutions to equations (Opens a modal)
• Worked example: number of solutions to equations (Opens a modal)
• Creating an equation with no solutions (Opens a modal)
• Creating an equation with infinitely many solutions (Opens a modal)
• Number of solutions to equations Get 3 of 4 questions to level up!
• Number of solutions to equations challenge Get 3 of 4 questions to level up!

## Linear equations with unknown coefficients

• Linear equations with unknown coefficients (Opens a modal)
• Why is algebra important to learn? (Opens a modal)
• Linear equations with unknown coefficients Get 3 of 4 questions to level up!

## Multi-step inequalities

• Inequalities with variables on both sides (Opens a modal)
• Inequalities with variables on both sides (with parentheses) (Opens a modal)
• Multi-step inequalities (Opens a modal)
• Using inequalities to solve problems (Opens a modal)
• Multi-step linear inequalities Get 3 of 4 questions to level up!
• Using inequalities to solve problems Get 3 of 4 questions to level up!

## Compound inequalities

• Compound inequalities: OR (Opens a modal)
• Compound inequalities: AND (Opens a modal)
• A compound inequality with no solution (Opens a modal)
• Double inequalities (Opens a modal)
• Compound inequalities examples (Opens a modal)
• Compound inequalities review (Opens a modal)
• Solving equations & inequalities: FAQ (Opens a modal)
• Compound inequalities Get 3 of 4 questions to level up!

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## Chapter 3 Review Exercises

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## 3.1 Using a Problem Solving Strategy

Approach Word Problems with a Positive Attitude

In the following exercises, reflect on your approach to word problems.

## Exercise $$\PageIndex{1}$$

How has your attitude towards solving word problems changed as a result of working through this chapter? Explain.

## Exercise $$\PageIndex{2}$$

Did the problem-solving strategy help you solve word problems in this chapter? Explain.

Use a Problem-Solving Strategy for Word Problems

In the following exercises, solve using the problem-solving strategy for word problems. Remember to write a complete sentence to answer each question.

## Exercise $$\PageIndex{3}$$

Three-fourths of the people at a concert are children. If there are 87 children, what is the total number of people at the concert?

## Exercise $$\PageIndex{4}$$

There are nine saxophone players in the band. The number of saxophone players is one less than twice the number of tuba players. Find the number of tuba players.

Solve Number Problems

In the following exercises, solve each number word problem.

## Exercise $$\PageIndex{5}$$

The sum of a number and three is forty-one. Find the number.

## Exercise $$\PageIndex{6}$$

Twice the difference of a number and ten is fifty-four. Find the number.

## Exercise $$\PageIndex{7}$$

One number is nine less than another. Their sum is negative twenty-seven. Find the numbers.

−18,−9

## Exercise $$\PageIndex{8}$$

One number is eleven more than another. If their sum is increased by seventeen, the result is 90. Find the numbers.

## Exercise $$\PageIndex{9}$$

One number is two more than four times another. Their sum is −13. Find the numbers.

−3,−10

## Exercise $$\PageIndex{10}$$

The sum of two consecutive integers is −135. Find the numbers.

## Exercise $$\PageIndex{11}$$

Find three consecutive integers whose sum is −141.

−48,−47,−46

## Exercise $$\PageIndex{12}$$

Find three consecutive even integers whose sum is 234.

## Exercise $$\PageIndex{13}$$

Find three consecutive odd integers whose sum is 51.

## Exercise $$\PageIndex{14}$$

Koji has $5,502 in his savings account. This is$30 less than six times the amount in his checking account. How much money does Koji have in his checking account?

## 3.2 Solve Percent Applications

Translate and Solve Basic Percent Equations

In the following exercises, translate and solve.

## Exercise $$\PageIndex{15}$$

What number is 67% of 250?

## Exercise $$\PageIndex{16}$$

300% of 82 is what number?

## Exercise $$\PageIndex{17}$$

12.5% of what number is 20?

## Exercise $$\PageIndex{18}$$

72 is 30% of what number?

## Exercise $$\PageIndex{19}$$

What percent of 125 is 150?

## Exercise $$\PageIndex{20}$$

127.5 is what percent of 850?

Solve Percent Applications

In the following exercises, solve.

## Exercise $$\PageIndex{24}$$

Jaden earns $2,680 per month. He pays$938 a month for rent. What percent of his monthly pay goes to rent?

Find Percent Increase and Percent Decrease

## Exercise $$\PageIndex{25}$$

Angel’s got a raise in his annual salary from $55,400 to$56,785. Find the percent increase.

## Exercise $$\PageIndex{26}$$

Rowena’s monthly gasoline bill dropped from $83.75 last month to$56.95 this month. Find the percent decrease.

Solve Simple Interest Applications

Jaime’s refrigerator loan statement said he would pay $1,026 in interest for a 4-year loan at 13.5%. How much did Jaime borrow to buy the refrigerator? ## Exercise $$\PageIndex{30}$$ In 12 years, a bond that paid 6.35% interest earned$7,620 interest. What was the principal of the bond?

Solve Applications with Discount or Mark-up

In the following exercises, find the sale price.

## Exercise $$\PageIndex{31}$$

The original price of a handbag was $84. Carole bought it on sale for$21 off.

## Exercise $$\PageIndex{32}$$

Marian wants to buy a coffee table that costs $495. Next week the coffee table will be on sale for$149 off.

In the following exercises, find

• the amount of discount and
• the sale price.

Emmett bought a pair of shoes on sale at 40% off from an original price of $138. ## Exercise $$\PageIndex{34}$$ Anastasia bought a dress on sale at 75% off from an original price of$280.

In the following exercises, find ⓐ the amount of discount and ⓑ the discount rate. (Round to the nearest tenth of a percent, if needed.)

## Exercise $$\PageIndex{35}$$

Zack bought a printer for his office that was on sale for $380. The original price of the printer was$450.

## Exercise $$\PageIndex{36}$$

Lacey bought a pair of boots on sale for $95. The original price of the boots was$200.

• the amount of the mark-up and
• the list price.

## 3.3 Solve Mixture Applications

Solve Coin Word Problems

In the following exercises, solve each coin word problem.

Paulette has $140 in$5 and $10 bills. The number of$10 bills is one less than twice the number of $5 bills. How many of each does she have? six$5 bills, 11 $10 bills ## Exercise $$\PageIndex{42}$$ Lenny has$3.69 in pennies, dimes, and quarters. The number of pennies is three more than the number of dimes. The number of quarters is twice the number of dimes. How many of each coin does he have?

Solve Ticket and Stamp Word Problems

In the following exercises, solve each ticket or stamp word problem.

Ana spent $4.06 buying stamps. The number of$0.41 stamps she bought was five more than the number of $0.26 stamps. How many of each did she buy? three$0.26 stamps, eight $0.41 stamps ## Exercise $$\PageIndex{48}$$ Yumi spent$34.15 buying stamps. The number of $0.56 stamps she bought was 10 less than four times the number of$0.41 stamps. How many of each did she buy?

Solve Mixture Word Problems

In the following exercises, solve each mixture word problem.

## 3.4 Solve Geometry Applications: Triangles, Rectangles and the Pythagorean Theorem

Solve Applications Using Triangle Properties

In the following exercises, solve using triangle properties.

## Exercise $$\PageIndex{53}$$

The measures of two angles of a triangle are 22 and 85 degrees. Find the measure of the third angle.

## Exercise $$\PageIndex{54}$$

The playground at a shopping mall is a triangle with perimeter 48 feet. The lengths of two sides are 19 feet and 14 feet. How long is the third side?

## Exercise $$\PageIndex{55}$$

A triangular road sign has base 30 inches and height 40 inches. What is its area?

600 square inches

## Exercise $$\PageIndex{56}$$

What is the height of a triangle with area 67.5 square meters and base 9 meters?

## Exercise $$\PageIndex{57}$$

One angle of a triangle is 30° more than the smallest angle. The largest angle is the sum of the other angles. Find the measures of all three angles.

30°,60°,90°

## Exercise $$\PageIndex{58}$$

One angle of a right triangle measures 58°. What is the measure of the other angles of the triangle?

## Exercise $$\PageIndex{59}$$

The measure of the smallest angle in a right triangle is 45° less than the measure of the next larger angle. Find the measures of all three angles.

22.5°,67.5°,90°

## Exercise $$\PageIndex{60}$$

The perimeter of a triangle is 97 feet. One side of the triangle is eleven feet more than the smallest side. The third side is six feet more than twice the smallest side. Find the lengths of all sides.

Use the Pythagorean Theorem

In the following exercises, use the Pythagorean Theorem to find the length of the hypotenuse.

## Exercise $$\PageIndex{62}$$

In the following exercises, use the Pythagorean Theorem to find the length of the missing side. Round to the nearest tenth, if necessary.

## Exercise $$\PageIndex{66}$$

In the following exercises, solve. Approximate to the nearest tenth, if necessary.

## Exercise $$\PageIndex{67}$$

Sergio needs to attach a wire to hold the antenna to the roof of his house, as shown in the figure. The antenna is 8 feet tall and Sergio has 10 feet of wire. How far from the base of the antenna can he attach the wire?

$$6^{\prime}$$

## Exercise $$\PageIndex{68}$$

Seong is building shelving in his garage. The shelves are 36 inches wide and 15 inches tall. He wants to put a diagonal brace across the back to stabilize the shelves, as shown. How long should the brace be?

Solve Applications Using Rectangle Properties

In the following exercises, solve using rectangle properties.

## Exercise $$\PageIndex{69}$$

The length of a rectangle is 36 feet and the width is 19 feet. Find the

• 684 sq. ft.

## Exercise $$\PageIndex{70}$$

A sidewalk in front of Kathy’s house is in the shape of a rectangle four feet wide by 45 feet long. Find the

## Exercise $$\PageIndex{71}$$

The area of a rectangle is 2356 square meters. The length is 38 meters. What is the width?

## Exercise $$\PageIndex{72}$$

The width of a rectangle is 45 centimeters. The area is 2,700 square centimeters. What is the length?

## Exercise $$\PageIndex{73}$$

The length of a rectangle is 12 cm more than the width. The perimeter is 74 cm. Find the length and the width.

24.5 cm, 12.5 cm

## Exercise $$\PageIndex{74}$$

The width of a rectangle is three more than twice the length. The perimeter is 96 inches. Find the length and the width.

## 3.5 Solve Uniform Motion Applications

Solve Uniform Motion Applications

## Exercise $$\PageIndex{75}$$

When Gabe drives from Sacramento to Redding it takes him 2.2 hours. It takes Elsa 2 hours to drive the same distance. Elsa’s speed is seven miles per hour faster than Gabe’s speed. Find Gabe’s speed and Elsa’s speed.

Gabe 70 mph, Elsa 77 mph

## Exercise $$\PageIndex{76}$$

Louellen and Tracy met at a restaurant on the road between Chicago and Nashville. Louellen had left Chicago and drove 3.2 hours towards Nashville. Tracy had left Nashville and drove 4 hours towards Chicago, at a speed one mile per hour faster than Louellen’s speed. The distance between Chicago and Nashville is 472 miles. Find Louellen’s speed and Tracy’s speed.

## Exercise $$\PageIndex{77}$$

Two busses leave Amarillo at the same time. The Albuquerque bus heads west on the I-40 at a speed of 72 miles per hour, and the Oklahoma City bus heads east on the I-40 at a speed of 78 miles per hour. How many hours will it take them to be 375 miles apart?

## Exercise $$\PageIndex{78}$$

Kyle rowed his boat upstream for 50 minutes. It took him 30 minutes to row back downstream. His speed going upstream is two miles per hour slower than his speed going downstream. Find Kyle’s upstream and downstream speeds.

## Exercise $$\PageIndex{79}$$

At 6:30, Devon left her house and rode her bike on the flat road until 7:30. Then she started riding uphill and rode until 8:00. She rode a total of 15 miles. Her speed on the flat road was three miles per hour faster than her speed going uphill. Find Devon’s speed on the flat road and riding uphill.

flat road 11 mph, uphill 8 mph

## Exercise $$\PageIndex{80}$$

Anthony drove from New York City to Baltimore, a distance of 192 miles. He left at 3:45 and had heavy traffic until 5:30. Traffic was light for the rest of the drive, and he arrived at 7:30. His speed in light traffic was four miles per hour more than twice his speed in heavy traffic. Find Anthony’s driving speed in heavy traffic and light traffic.

## 3.6 Solve Applications with Linear Inequalities

Solve Applications with Linear Inequalities

## Exercise $$\PageIndex{81}$$

Julianne has a weekly food budget of $231 for her family. If she plans to budget the same amount for each of the seven days of the week, what is the maximum amount she can spend on food each day?$33 per day

## Exercise $$\PageIndex{82}$$

Rogelio paints watercolors. He got a $100 gift card to the art supply store and wants to use it to buy $$12^{\prime \prime} \times 16^{\prime \prime}$$ canvases. Each canvas costs$10.99. What is the maximum number of canvases he can buy with his gift card?

## Exercise $$\PageIndex{83}$$

Briana has been offered a sales job in another city. The offer was for $42,500 plus 8% of her total sales. In order to make it worth the move, Briana needs to have an annual salary of at least$66,500. What would her total sales need to be for her to move?

## Practice Test

Exercise $$\pageindex{87}$$.

Four-fifths of the people on a hike are children. If there are 12 children, what is the total number of people on the hike?

## Exercise $$\PageIndex{88}$$

One number is three more than twice another. Their sum is −63. Find the numbers.

## Exercise $$\PageIndex{89}$$

The sum of two consecutive odd integers is −96. Find the numbers.

−49,−47

## Exercise $$\PageIndex{90}$$

Marla’s breakfast was 525 calories. This was 35% of her total calories for the day. How many calories did she have that day?

## Exercise $$\PageIndex{91}$$

Humberto’s hourly pay increased from $16.25 to$17.55. Find the percent increase.

## Exercise $$\PageIndex{97}$$

The measure of one angle of a triangle is twice the measure of the smallest angle. The measure of the third angle is 14 more than the measure of the smallest angle. Find the measures of all three angles.

41.5°,55.5°,83°

## Exercise $$\PageIndex{98}$$

What is the height of a triangle with area 277.2 square inches and base 44 inches?

## Exercise $$\PageIndex{101}$$

A baseball diamond is really a square with sides of 90 feet. How far is it from home plate to second base, as shown?

## Exercise $$\PageIndex{102}$$

The length of a rectangle is two feet more than five times the width. The perimeter is 40 feet. Find the dimensions of the rectangle.

## Exercise $$\PageIndex{103}$$

Two planes leave Dallas at the same time. One heads east at a speed of 428 miles per hour. The other plane heads west at a speed of 382 miles per hour. How many hours will it take them to be 2,025 miles apart?

## Exercise $$\PageIndex{104}$$

Leon drove from his house in Cincinnati to his sister’s house in Cleveland, a distance of 252 miles. It took him 412412 hours. For the first half hour he had heavy traffic, and the rest of the time his speed was five miles per hour less than twice his speed in heavy traffic. What was his speed in heavy traffic?

## Exercise $$\PageIndex{105}$$

Chloe has a budget of $800 for costumes for the 18 members of her musical theater group. What is the maximum she can spend for each costume? at most$44.44 per costume

Frank found a rental car deal online for $49 per week plus$0.24 per mile. How many miles could he drive if he wants the total cost for one week to be no more than $150? ## 3.1 Functions and Function Notation • ⓑ yes (Note: If two players had been tied for, say, 4th place, then the name would not have been a function of rank.) w = f ( d ) w = f ( d ) g ( 5 ) = 1 g ( 5 ) = 1 m = 8 m = 8 y = f ( x ) = x 3 2 y = f ( x ) = x 3 2 g ( 1 ) = 8 g ( 1 ) = 8 x = 0 x = 0 or x = 2 x = 2 • ⓐ yes, because each bank account has a single balance at any given time; • ⓑ no, because several bank account numbers may have the same balance; • ⓒ no, because the same output may correspond to more than one input. • ⓐ Yes, letter grade is a function of percent grade; • ⓑ No, it is not one-to-one. There are 100 different percent numbers we could get but only about five possible letter grades, so there cannot be only one percent number that corresponds to each letter grade. No, because it does not pass the horizontal line test. ## 3.2 Domain and Range { − 5 , 0 , 5 , 10 , 15 } { − 5 , 0 , 5 , 10 , 15 } ( − ∞ , ∞ ) ( − ∞ , ∞ ) ( − ∞ , 1 2 ) ∪ ( 1 2 , ∞ ) ( − ∞ , 1 2 ) ∪ ( 1 2 , ∞ ) [ − 5 2 , ∞ ) [ − 5 2 , ∞ ) • ⓐ values that are less than or equal to –2, or values that are greater than or equal to –1 and less than 3 • ⓑ { x | x ≤ − 2 or − 1 ≤ x < 3 } { x | x ≤ − 2 or − 1 ≤ x < 3 } • ⓒ ( − ∞ , − 2 ] ∪ [ − 1 , 3 ) ( − ∞ , − 2 ] ∪ [ − 1 , 3 ) domain =[1950,2002] range = [47,000,000,89,000,000] domain: ( − ∞ , 2 ] ; ( − ∞ , 2 ] ; range: ( − ∞ , 0 ] ( − ∞ , 0 ] ## 3.3 Rates of Change and Behavior of Graphs$ 2.84 − $2.31 5 years =$ 0.53 5 years = $0.106$ 2.84 − $2.31 5 years =$ 0.53 5 years = $0.106 per year. a + 7 a + 7 The local maximum appears to occur at ( − 1 , 28 ) , ( − 1 , 28 ) , and the local minimum occurs at ( 5 , − 80 ) . ( 5 , − 80 ) . The function is increasing on ( − ∞ , − 1 ) ∪ ( 5 , ∞ ) ( − ∞ , − 1 ) ∪ ( 5 , ∞ ) and decreasing on ( − 1 , 5 ) . ( − 1 , 5 ) . ## 3.4 Composition of Functions ( f g ) ( x ) = f ( x ) g ( x ) = ( x − 1 ) ( x 2 − 1 ) = x 3 − x 2 − x + 1 ( f − g ) ( x ) = f ( x ) − g ( x ) = ( x − 1 ) − ( x 2 − 1 ) = x − x 2 ( f g ) ( x ) = f ( x ) g ( x ) = ( x − 1 ) ( x 2 − 1 ) = x 3 − x 2 − x + 1 ( f − g ) ( x ) = f ( x ) − g ( x ) = ( x − 1 ) − ( x 2 − 1 ) = x − x 2 No, the functions are not the same. A gravitational force is still a force, so a ( G ( r ) ) a ( G ( r ) ) makes sense as the acceleration of a planet at a distance r from the Sun (due to gravity), but G ( a ( F ) ) G ( a ( F ) ) does not make sense. f ( g ( 1 ) ) = f ( 3 ) = 3 f ( g ( 1 ) ) = f ( 3 ) = 3 and g ( f ( 4 ) ) = g ( 1 ) = 3 g ( f ( 4 ) ) = g ( 1 ) = 3 g ( f ( 2 ) ) = g ( 5 ) = 3 g ( f ( 2 ) ) = g ( 5 ) = 3 [ − 4 , 0 ) ∪ ( 0 , ∞ ) [ − 4 , 0 ) ∪ ( 0 , ∞ ) Possible answer: g ( x ) = 4 + x 2 h ( x ) = 4 3 − x f = h ∘ g g ( x ) = 4 + x 2 h ( x ) = 4 3 − x f = h ∘ g ## 3.5 Transformation of Functions The graphs of f ( x ) f ( x ) and g ( x ) g ( x ) are shown below. The transformation is a horizontal shift. The function is shifted to the left by 2 units. g ( x ) = 1 x - 1 + 1 g ( x ) = 1 x - 1 + 1 g ( x ) = − f ( x ) g ( x ) = − f ( x ) h ( x ) = f ( − x ) h ( x ) = f ( − x ) Notice: g ( x ) = f ( − x ) g ( x ) = f ( − x ) looks the same as f ( x ) f ( x ) . g ( x ) = 3 x - 2 g ( x ) = 3 x - 2 g ( x ) = f ( 1 3 x ) g ( x ) = f ( 1 3 x ) so using the square root function we get g ( x ) = 1 3 x g ( x ) = 1 3 x ## 3.6 Absolute Value Functions using the variable p p for passing, | p − 80 | ≤ 20 | p − 80 | ≤ 20 f ( x ) = − | x + 2 | + 3 f ( x ) = − | x + 2 | + 3 x = − 1 x = − 1 or x = 2 x = 2 ## 3.7 Inverse Functions h ( 2 ) = 6 h ( 2 ) = 6 The domain of function f − 1 f − 1 is ( − ∞ , − 2 ) ( − ∞ , − 2 ) and the range of function f − 1 f − 1 is ( 1 , ∞ ) . ( 1 , ∞ ) . • ⓐ f ( 60 ) = 50. f ( 60 ) = 50. In 60 minutes, 50 miles are traveled. • ⓑ f − 1 ( 60 ) = 70. f − 1 ( 60 ) = 70. To travel 60 miles, it will take 70 minutes. x = 3 y + 5 x = 3 y + 5 f − 1 ( x ) = ( 2 − x ) 2 ; domain of f : [ 0 , ∞ ) ; domain of f − 1 : ( − ∞ , 2 ] f − 1 ( x ) = ( 2 − x ) 2 ; domain of f : [ 0 , ∞ ) ; domain of f − 1 : ( − ∞ , 2 ] ## 3.1 Section Exercises A relation is a set of ordered pairs. A function is a special kind of relation in which no two ordered pairs have the same first coordinate. When a vertical line intersects the graph of a relation more than once, that indicates that for that input there is more than one output. At any particular input value, there can be only one output if the relation is to be a function. When a horizontal line intersects the graph of a function more than once, that indicates that for that output there is more than one input. A function is one-to-one if each output corresponds to only one input. not a function f ( − 3 ) = − 11 ; f ( − 3 ) = − 11 ; f ( 2 ) = − 1 ; f ( 2 ) = − 1 ; f ( − a ) = − 2 a − 5 ; f ( − a ) = − 2 a − 5 ; − f ( a ) = − 2 a + 5 ; − f ( a ) = − 2 a + 5 ; f ( a + h ) = 2 a + 2 h − 5 f ( a + h ) = 2 a + 2 h − 5 f ( − 3 ) = 5 + 5 ; f ( − 3 ) = 5 + 5 ; f ( 2 ) = 5 ; f ( 2 ) = 5 ; f ( − a ) = 2 + a + 5 ; f ( − a ) = 2 + a + 5 ; − f ( a ) = − 2 − a − 5 ; − f ( a ) = − 2 − a − 5 ; f ( a + h ) = 2 − a − h + 5 f ( a + h ) = 2 − a − h + 5 f ( − 3 ) = 2 ; f ( − 3 ) = 2 ; f ( 2 ) = 1 − 3 = − 2 ; f ( 2 ) = 1 − 3 = − 2 ; f ( − a ) = | − a − 1 | − | − a + 1 | ; f ( − a ) = | − a − 1 | − | − a + 1 | ; − f ( a ) = − | a − 1 | + | a + 1 | ; − f ( a ) = − | a − 1 | + | a + 1 | ; f ( a + h ) = | a + h − 1 | − | a + h + 1 | f ( a + h ) = | a + h − 1 | − | a + h + 1 | g ( x ) − g ( a ) x − a = x + a + 2 , x ≠ a g ( x ) − g ( a ) x − a = x + a + 2 , x ≠ a a. f ( − 2 ) = 14 ; f ( − 2 ) = 14 ; b. x = 3 x = 3 a. f ( 5 ) = 10 ; f ( 5 ) = 10 ; b. x = − 1 x = − 1 or x = 4 x = 4 • ⓐ f ( t ) = 6 − 2 3 t ; f ( t ) = 6 − 2 3 t ; • ⓑ f ( − 3 ) = 8 ; f ( − 3 ) = 8 ; • ⓒ t = 6 t = 6 • ⓐ f ( 0 ) = 1 ; f ( 0 ) = 1 ; • ⓑ f ( x ) = − 3 , x = − 2 f ( x ) = − 3 , x = − 2 or x = 2 x = 2 not a function so it is also not a one-to-one function one-to- one function function, but not one-to-one f ( x ) = 1 , x = 2 f ( x ) = 1 , x = 2 f ( − 2 ) = 14 ; f ( − 1 ) = 11 ; f ( 0 ) = 8 ; f ( 1 ) = 5 ; f ( 2 ) = 2 f ( − 2 ) = 14 ; f ( − 1 ) = 11 ; f ( 0 ) = 8 ; f ( 1 ) = 5 ; f ( 2 ) = 2 f ( − 2 ) = 4 ; f ( − 1 ) = 4.414 ; f ( 0 ) = 4.732 ; f ( 1 ) = 5 ; f ( 2 ) = 5.236 f ( − 2 ) = 4 ; f ( − 1 ) = 4.414 ; f ( 0 ) = 4.732 ; f ( 1 ) = 5 ; f ( 2 ) = 5.236 f ( − 2 ) = 1 9 ; f ( − 1 ) = 1 3 ; f ( 0 ) = 1 ; f ( 1 ) = 3 ; f ( 2 ) = 9 f ( − 2 ) = 1 9 ; f ( − 1 ) = 1 3 ; f ( 0 ) = 1 ; f ( 1 ) = 3 ; f ( 2 ) = 9 [ 0 , 100 ] [ 0 , 100 ] [ − 0.001 , 0 .001 ] [ − 0.001 , 0 .001 ] [ − 1 , 000 , 000 , 1,000,000 ] [ − 1 , 000 , 000 , 1,000,000 ] [ 0 , 10 ] [ 0 , 10 ] [ −0.1 , 0.1 ] [ −0.1 , 0.1 ] [ − 100 , 100 ] [ − 100 , 100 ] • ⓐ g ( 5000 ) = 50 ; g ( 5000 ) = 50 ; • ⓑ The number of cubic yards of dirt required for a garden of 100 square feet is 1. • ⓐ The height of a rocket above ground after 1 second is 200 ft. • ⓑ The height of a rocket above ground after 2 seconds is 350 ft. ## 3.2 Section Exercises The domain of a function depends upon what values of the independent variable make the function undefined or imaginary. There is no restriction on x x for f ( x ) = x 3 f ( x ) = x 3 because you can take the cube root of any real number. So the domain is all real numbers, ( − ∞ , ∞ ) . ( − ∞ , ∞ ) . When dealing with the set of real numbers, you cannot take the square root of negative numbers. So x x -values are restricted for f ( x ) = x f ( x ) = x to nonnegative numbers and the domain is [ 0 , ∞ ) . [ 0 , ∞ ) . Graph each formula of the piecewise function over its corresponding domain. Use the same scale for the x x -axis and y y -axis for each graph. Indicate inclusive endpoints with a solid circle and exclusive endpoints with an open circle. Use an arrow to indicate − ∞ − ∞ or ∞ . ∞ . Combine the graphs to find the graph of the piecewise function. ( − ∞ , 3 ] ( − ∞ , 3 ] ( − ∞ , − 1 2 ) ∪ ( − 1 2 , ∞ ) ( − ∞ , − 1 2 ) ∪ ( − 1 2 , ∞ ) ( − ∞ , − 11 ) ∪ ( − 11 , 2 ) ∪ ( 2 , ∞ ) ( − ∞ , − 11 ) ∪ ( − 11 , 2 ) ∪ ( 2 , ∞ ) ( − ∞ , − 3 ) ∪ ( − 3 , 5 ) ∪ ( 5 , ∞ ) ( − ∞ , − 3 ) ∪ ( − 3 , 5 ) ∪ ( 5 , ∞ ) ( − ∞ , 5 ) ( − ∞ , 5 ) [ 6 , ∞ ) [ 6 , ∞ ) ( − ∞ , − 9 ) ∪ ( − 9 , 9 ) ∪ ( 9 , ∞ ) ( − ∞ , − 9 ) ∪ ( − 9 , 9 ) ∪ ( 9 , ∞ ) domain: ( 2 , 8 ] , ( 2 , 8 ] , range [ 6 , 8 ) [ 6 , 8 ) domain: [ − 4 , 4], [ − 4 , 4], range: [ 0 , 2] [ 0 , 2] domain: [ − 5 , 3 ) , [ − 5 , 3 ) , range: [ 0 , 2 ] [ 0 , 2 ] domain: ( − ∞ , 1 ] , ( − ∞ , 1 ] , range: [ 0 , ∞ ) [ 0 , ∞ ) domain: [ − 6 , − 1 6 ] ∪ [ 1 6 , 6 ] ; [ − 6 , − 1 6 ] ∪ [ 1 6 , 6 ] ; range: [ − 6 , − 1 6 ] ∪ [ 1 6 , 6 ] [ − 6 , − 1 6 ] ∪ [ 1 6 , 6 ] domain: [ − 3 , ∞ ) ; [ − 3 , ∞ ) ; range: [ 0 , ∞ ) [ 0 , ∞ ) domain: ( − ∞ , ∞ ) ( − ∞ , ∞ ) f ( − 3 ) = 1 ; f ( − 2 ) = 0 ; f ( − 1 ) = 0 ; f ( 0 ) = 0 f ( − 3 ) = 1 ; f ( − 2 ) = 0 ; f ( − 1 ) = 0 ; f ( 0 ) = 0 f ( − 1 ) = − 4 ; f ( 0 ) = 6 ; f ( 2 ) = 20 ; f ( 4 ) = 34 f ( − 1 ) = − 4 ; f ( 0 ) = 6 ; f ( 2 ) = 20 ; f ( 4 ) = 34 f ( − 1 ) = − 5 ; f ( 0 ) = 3 ; f ( 2 ) = 3 ; f ( 4 ) = 16 f ( − 1 ) = − 5 ; f ( 0 ) = 3 ; f ( 2 ) = 3 ; f ( 4 ) = 16 domain: ( − ∞ , 1 ) ∪ ( 1 , ∞ ) ( − ∞ , 1 ) ∪ ( 1 , ∞ ) window: [ − 0.5 , − 0.1 ] ; [ − 0.5 , − 0.1 ] ; range: [ 4 , 100 ] [ 4 , 100 ] window: [ 0.1 , 0.5 ] ; [ 0.1 , 0.5 ] ; range: [ 4 , 100 ] [ 4 , 100 ] [ 0 , 8 ] [ 0 , 8 ] Many answers. One function is f ( x ) = 1 x − 2 . f ( x ) = 1 x − 2 . • ⓐ The fixed cost is$500.
• ⓑ The cost of making 25 items is 750. • ⓒ The domain is [0, 100] and the range is [500, 1500]. ## 3.3 Section Exercises Yes, the average rate of change of all linear functions is constant. The absolute maximum and minimum relate to the entire graph, whereas the local extrema relate only to a specific region around an open interval. 4 ( b + 1 ) 4 ( b + 1 ) 4 x + 2 h 4 x + 2 h − 1 13 ( 13 + h ) − 1 13 ( 13 + h ) 3 h 2 + 9 h + 9 3 h 2 + 9 h + 9 4 x + 2 h − 3 4 x + 2 h − 3 increasing on ( − ∞ , − 2.5 ) ∪ ( 1 , ∞ ) , ( − ∞ , − 2.5 ) ∪ ( 1 , ∞ ) , decreasing on ( − 2.5 , 1 ) ( − 2.5 , 1 ) increasing on ( − ∞ , 1 ) ∪ ( 3 , 4 ) , ( − ∞ , 1 ) ∪ ( 3 , 4 ) , decreasing on ( 1 , 3 ) ∪ ( 4 , ∞ ) ( 1 , 3 ) ∪ ( 4 , ∞ ) local maximum: ( − 3 , 60 ) , ( − 3 , 60 ) , local minimum: ( 3 , − 60 ) ( 3 , − 60 ) absolute maximum at approximately ( 7 , 150 ) , ( 7 , 150 ) , absolute minimum at approximately ( −7.5 , −220 ) ( −7.5 , −220 ) Local minimum at ( 3 , − 22 ) , ( 3 , − 22 ) , decreasing on ( − ∞ , 3 ) , ( − ∞ , 3 ) , increasing on ( 3 , ∞ ) ( 3 , ∞ ) Local minimum at ( − 2 , − 2 ) , ( − 2 , − 2 ) , decreasing on ( − 3 , − 2 ) , ( − 3 , − 2 ) , increasing on ( − 2 , ∞ ) ( − 2 , ∞ ) Local maximum at ( − 0.5 , 6 ) , ( − 0.5 , 6 ) , local minima at ( − 3.25 , − 47 ) ( − 3.25 , − 47 ) and ( 2.1 , − 32 ) , ( 2.1 , − 32 ) , decreasing on ( − ∞ , − 3.25 ) ( − ∞ , − 3.25 ) and ( − 0.5 , 2.1 ) , ( − 0.5 , 2.1 ) , increasing on ( − 3.25 , − 0.5 ) ( − 3.25 , − 0.5 ) and ( 2.1 , ∞ ) ( 2.1 , ∞ ) b = 5 b = 5 2.7 gallons per minute approximately –0.6 milligrams per day ## 3.4 Section Exercises Find the numbers that make the function in the denominator g g equal to zero, and check for any other domain restrictions on f f and g , g , such as an even-indexed root or zeros in the denominator. Yes. Sample answer: Let f ( x ) = x + 1 and g ( x ) = x − 1. f ( x ) = x + 1 and g ( x ) = x − 1. Then f ( g ( x ) ) = f ( x − 1 ) = ( x − 1 ) + 1 = x f ( g ( x ) ) = f ( x − 1 ) = ( x − 1 ) + 1 = x and g ( f ( x ) ) = g ( x + 1 ) = ( x + 1 ) − 1 = x . g ( f ( x ) ) = g ( x + 1 ) = ( x + 1 ) − 1 = x . So f ∘ g = g ∘ f . f ∘ g = g ∘ f . ( f + g ) ( x ) = 2 x + 6 , ( f + g ) ( x ) = 2 x + 6 , domain: ( − ∞ , ∞ ) ( − ∞ , ∞ ) ( f − g ) ( x ) = 2 x 2 + 2 x − 6 , ( f − g ) ( x ) = 2 x 2 + 2 x − 6 , domain: ( − ∞ , ∞ ) ( − ∞ , ∞ ) ( f g ) ( x ) = − x 4 − 2 x 3 + 6 x 2 + 12 x , ( f g ) ( x ) = − x 4 − 2 x 3 + 6 x 2 + 12 x , domain: ( − ∞ , ∞ ) ( − ∞ , ∞ ) ( f g ) ( x ) = x 2 + 2 x 6 − x 2 , ( f g ) ( x ) = x 2 + 2 x 6 − x 2 , domain: ( − ∞ , − 6 ) ∪ ( − 6 , 6 ) ∪ ( 6 , ∞ ) ( − ∞ , − 6 ) ∪ ( − 6 , 6 ) ∪ ( 6 , ∞ ) ( f + g ) ( x ) = 4 x 3 + 8 x 2 + 1 2 x , ( f + g ) ( x ) = 4 x 3 + 8 x 2 + 1 2 x , domain: ( − ∞ , 0 ) ∪ ( 0 , ∞ ) ( − ∞ , 0 ) ∪ ( 0 , ∞ ) ( f − g ) ( x ) = 4 x 3 + 8 x 2 − 1 2 x , ( f − g ) ( x ) = 4 x 3 + 8 x 2 − 1 2 x , domain: ( − ∞ , 0 ) ∪ ( 0 , ∞ ) ( − ∞ , 0 ) ∪ ( 0 , ∞ ) ( f g ) ( x ) = x + 2 , ( f g ) ( x ) = x + 2 , domain: ( − ∞ , 0 ) ∪ ( 0 , ∞ ) ( − ∞ , 0 ) ∪ ( 0 , ∞ ) ( f g ) ( x ) = 4 x 3 + 8 x 2 , ( f g ) ( x ) = 4 x 3 + 8 x 2 , domain: ( − ∞ , 0 ) ∪ ( 0 , ∞ ) ( − ∞ , 0 ) ∪ ( 0 , ∞ ) ( f + g ) ( x ) = 3 x 2 + x − 5 , ( f + g ) ( x ) = 3 x 2 + x − 5 , domain: [ 5 , ∞ ) [ 5 , ∞ ) ( f − g ) ( x ) = 3 x 2 − x − 5 , ( f − g ) ( x ) = 3 x 2 − x − 5 , domain: [ 5 , ∞ ) [ 5 , ∞ ) ( f g ) ( x ) = 3 x 2 x − 5 , ( f g ) ( x ) = 3 x 2 x − 5 , domain: [ 5 , ∞ ) [ 5 , ∞ ) ( f g ) ( x ) = 3 x 2 x − 5 , ( f g ) ( x ) = 3 x 2 x − 5 , domain: ( 5 , ∞ ) ( 5 , ∞ ) • ⓑ f ( g ( x ) ) = 2 ( 3 x − 5 ) 2 + 1 f ( g ( x ) ) = 2 ( 3 x − 5 ) 2 + 1 • ⓒ f ( g ( x ) ) = 6 x 2 − 2 f ( g ( x ) ) = 6 x 2 − 2 • ⓓ ( g ∘ g ) ( x ) = 3 ( 3 x − 5 ) − 5 = 9 x − 20 ( g ∘ g ) ( x ) = 3 ( 3 x − 5 ) − 5 = 9 x − 20 • ⓔ ( f ∘ f ) ( − 2 ) = 163 ( f ∘ f ) ( − 2 ) = 163 f ( g ( x ) ) = x 2 + 3 + 2 , g ( f ( x ) ) = x + 4 x + 7 f ( g ( x ) ) = x 2 + 3 + 2 , g ( f ( x ) ) = x + 4 x + 7 f ( g ( x ) ) = x + 1 x 3 3 = x + 1 3 x , g ( f ( x ) ) = x 3 + 1 x f ( g ( x ) ) = x + 1 x 3 3 = x + 1 3 x , g ( f ( x ) ) = x 3 + 1 x ( f ∘ g ) ( x ) = 1 2 x + 4 − 4 = x 2 , ( g ∘ f ) ( x ) = 2 x − 4 ( f ∘ g ) ( x ) = 1 2 x + 4 − 4 = x 2 , ( g ∘ f ) ( x ) = 2 x − 4 f ( g ( h ( x ) ) ) = ( 1 x + 3 ) 2 + 1 f ( g ( h ( x ) ) ) = ( 1 x + 3 ) 2 + 1 • ⓐ ( g ∘ f ) ( x ) = − 3 2 − 4 x ( g ∘ f ) ( x ) = − 3 2 − 4 x • ⓑ ( − ∞ , 1 2 ) ( − ∞ , 1 2 ) • ⓐ ( 0 , 2 ) ∪ ( 2 , ∞ ) ; ( 0 , 2 ) ∪ ( 2 , ∞ ) ; • ⓑ ( − ∞ , − 2 ) ∪ ( 2 , ∞ ) ; ( − ∞ , − 2 ) ∪ ( 2 , ∞ ) ; • ⓒ ( 0 , ∞ ) ( 0 , ∞ ) ( 1 , ∞ ) ( 1 , ∞ ) sample: f ( x ) = x 3 g ( x ) = x − 5 f ( x ) = x 3 g ( x ) = x − 5 sample: f ( x ) = 4 x g ( x ) = ( x + 2 ) 2 f ( x ) = 4 x g ( x ) = ( x + 2 ) 2 sample: f ( x ) = x 3 g ( x ) = 1 2 x − 3 f ( x ) = x 3 g ( x ) = 1 2 x − 3 sample: f ( x ) = x 4 g ( x ) = 3 x − 2 x + 5 f ( x ) = x 4 g ( x ) = 3 x − 2 x + 5 sample: f ( x ) = x g ( x ) = 2 x + 6 f ( x ) = x g ( x ) = 2 x + 6 sample: f ( x ) = x 3 g ( x ) = ( x − 1 ) f ( x ) = x 3 g ( x ) = ( x − 1 ) sample: f ( x ) = x 3 g ( x ) = 1 x − 2 f ( x ) = x 3 g ( x ) = 1 x − 2 sample: f ( x ) = x g ( x ) = 2 x − 1 3 x + 4 f ( x ) = x g ( x ) = 2 x − 1 3 x + 4 f ( g ( 0 ) ) = 27 , g ( f ( 0 ) ) = − 94 f ( g ( 0 ) ) = 27 , g ( f ( 0 ) ) = − 94 f ( g ( 0 ) ) = 1 5 , g ( f ( 0 ) ) = 5 f ( g ( 0 ) ) = 1 5 , g ( f ( 0 ) ) = 5 18 x 2 + 60 x + 51 18 x 2 + 60 x + 51 g ∘ g ( x ) = 9 x + 20 g ∘ g ( x ) = 9 x + 20 ( f ∘ g ) ( 6 ) = 6 ( f ∘ g ) ( 6 ) = 6 ; ( g ∘ f ) ( 6 ) = 6 ( g ∘ f ) ( 6 ) = 6 ( f ∘ g ) ( 11 ) = 11 , ( g ∘ f ) ( 11 ) = 11 ( f ∘ g ) ( 11 ) = 11 , ( g ∘ f ) ( 11 ) = 11 A ( t ) = π ( 25 t + 2 ) 2 A ( t ) = π ( 25 t + 2 ) 2 and A ( 2 ) = π ( 25 4 ) 2 = 2500 π A ( 2 ) = π ( 25 4 ) 2 = 2500 π square inches A ( 5 ) = π ( 2 ( 5 ) + 1 ) 2 = 121 π A ( 5 ) = π ( 2 ( 5 ) + 1 ) 2 = 121 π square units • ⓐ N ( T ( t ) ) = 23 ( 5 t + 1.5 ) 2 − 56 ( 5 t + 1.5 ) + 1 N ( T ( t ) ) = 23 ( 5 t + 1.5 ) 2 − 56 ( 5 t + 1.5 ) + 1 • ⓑ 3.38 hours ## 3.5 Section Exercises A horizontal shift results when a constant is added to or subtracted from the input. A vertical shifts results when a constant is added to or subtracted from the output. A horizontal compression results when a constant greater than 1 is multiplied by the input. A vertical compression results when a constant between 0 and 1 is multiplied by the output. For a function f , f , substitute ( − x ) ( − x ) for ( x ) ( x ) in f ( x ) . f ( x ) . Simplify. If the resulting function is the same as the original function, f ( − x ) = f ( x ) , f ( − x ) = f ( x ) , then the function is even. If the resulting function is the opposite of the original function, f ( − x ) = − f ( x ) , f ( − x ) = − f ( x ) , then the original function is odd. If the function is not the same or the opposite, then the function is neither odd nor even. g ( x ) = | x - 1 | − 3 g ( x ) = | x - 1 | − 3 g ( x ) = 1 ( x + 4 ) 2 + 2 g ( x ) = 1 ( x + 4 ) 2 + 2 The graph of f ( x + 43 ) f ( x + 43 ) is a horizontal shift to the left 43 units of the graph of f . f . The graph of f ( x - 4 ) f ( x - 4 ) is a horizontal shift to the right 4 units of the graph of f . f . The graph of f ( x ) + 8 f ( x ) + 8 is a vertical shift up 8 units of the graph of f . f . The graph of f ( x ) − 7 f ( x ) − 7 is a vertical shift down 7 units of the graph of f . f . The graph of f ( x + 4 ) − 1 f ( x + 4 ) − 1 is a horizontal shift to the left 4 units and a vertical shift down 1 unit of the graph of f . f . decreasing on ( − ∞ , − 3 ) ( − ∞ , − 3 ) and increasing on ( − 3 , ∞ ) ( − 3 , ∞ ) decreasing on ( 0 , ∞ ) ( 0 , ∞ ) g ( x ) = f ( x - 1 ) , h ( x ) = f ( x ) + 1 g ( x ) = f ( x - 1 ) , h ( x ) = f ( x ) + 1 f ( x ) = | x - 3 | − 2 f ( x ) = | x - 3 | − 2 f ( x ) = x + 3 − 1 f ( x ) = x + 3 − 1 f ( x ) = ( x - 2 ) 2 f ( x ) = ( x - 2 ) 2 f ( x ) = | x + 3 | − 2 f ( x ) = | x + 3 | − 2 f ( x ) = − x f ( x ) = − x f ( x ) = − ( x + 1 ) 2 + 2 f ( x ) = − ( x + 1 ) 2 + 2 f ( x ) = − x + 1 f ( x ) = − x + 1 The graph of g g is a vertical reflection (across the x x -axis) of the graph of f . f . The graph of g g is a vertical stretch by a factor of 4 of the graph of f . f . The graph of g g is a horizontal compression by a factor of 1 5 1 5 of the graph of f . f . The graph of g g is a horizontal stretch by a factor of 3 of the graph of f . f . The graph of g g is a horizontal reflection across the y y -axis and a vertical stretch by a factor of 3 of the graph of f . f . g ( x ) = | − 4 x | g ( x ) = | − 4 x | g ( x ) = 1 3 ( x + 2 ) 2 − 3 g ( x ) = 1 3 ( x + 2 ) 2 − 3 g ( x ) = 1 2 ( x - 5 ) 2 + 1 g ( x ) = 1 2 ( x - 5 ) 2 + 1 The graph of the function f ( x ) = x 2 f ( x ) = x 2 is shifted to the left 1 unit, stretched vertically by a factor of 4, and shifted down 5 units. The graph of f ( x ) = | x | f ( x ) = | x | is stretched vertically by a factor of 2, shifted horizontally 4 units to the right, reflected across the horizontal axis, and then shifted vertically 3 units up. The graph of the function f ( x ) = x 3 f ( x ) = x 3 is compressed vertically by a factor of 1 2 . 1 2 . The graph of the function is stretched horizontally by a factor of 3 and then shifted vertically downward by 3 units. The graph of f ( x ) = x f ( x ) = x is shifted right 4 units and then reflected across the vertical line x = 4. x = 4. ## 3.6 Section Exercises Isolate the absolute value term so that the equation is of the form | A | = B . | A | = B . Form one equation by setting the expression inside the absolute value symbol, A , A , equal to the expression on the other side of the equation, B . B . Form a second equation by setting A A equal to the opposite of the expression on the other side of the equation, − B . − B . Solve each equation for the variable. The graph of the absolute value function does not cross the x x -axis, so the graph is either completely above or completely below the x x -axis. The distance from x to 8 can be represented using the absolute value statement: ∣ x − 8 ∣ = 4. ∣ x − 10 ∣ ≥ 15 There are no x-intercepts. (−4, 0) and (2, 0) ( 0 , − 4 ) , ( 4 , 0 ) , ( − 2 , 0 ) ( 0 , − 4 ) , ( 4 , 0 ) , ( − 2 , 0 ) ( 0 , 7 ) , ( 25 , 0 ) , ( − 7 , 0 ) ( 0 , 7 ) , ( 25 , 0 ) , ( − 7 , 0 ) range: [ – 400 , 100 ] [ – 400 , 100 ] There is no solution for a a that will keep the function from having a y y -intercept. The absolute value function always crosses the y y -intercept when x = 0. x = 0. | p − 0.08 | ≤ 0.015 | p − 0.08 | ≤ 0.015 | x − 5.0 | ≤ 0.01 | x − 5.0 | ≤ 0.01 ## 3.7 Section Exercises Each output of a function must have exactly one output for the function to be one-to-one. If any horizontal line crosses the graph of a function more than once, that means that y y -values repeat and the function is not one-to-one. If no horizontal line crosses the graph of the function more than once, then no y y -values repeat and the function is one-to-one. Yes. For example, f ( x ) = 1 x f ( x ) = 1 x is its own inverse. Given a function y = f ( x ) , y = f ( x ) , solve for x x in terms of y . y . Interchange the x x and y . y . Solve the new equation for y . y . The expression for y y is the inverse, y = f − 1 ( x ) . y = f − 1 ( x ) . f − 1 ( x ) = x − 3 f − 1 ( x ) = x − 3 f − 1 ( x ) = 2 − x f − 1 ( x ) = 2 − x f − 1 ( x ) = − 2 x x − 1 f − 1 ( x ) = − 2 x x − 1 domain of f ( x ) : [ − 7 , ∞ ) ; f − 1 ( x ) = x − 7 f ( x ) : [ − 7 , ∞ ) ; f − 1 ( x ) = x − 7 domain of f ( x ) : [ 0 , ∞ ) ; f − 1 ( x ) = x + 5 f ( x ) : [ 0 , ∞ ) ; f − 1 ( x ) = x + 5 a. f ( g ( x ) ) = x f ( g ( x ) ) = x and g ( f ( x ) ) = x . g ( f ( x ) ) = x . b. This tells us that f f and g g are inverse functions f ( g ( x ) ) = x , g ( f ( x ) ) = x f ( g ( x ) ) = x , g ( f ( x ) ) = x not one-to-one [ 2 , 10 ] [ 2 , 10 ] f − 1 ( x ) = ( 1 + x ) 1 / 3 f − 1 ( x ) = ( 1 + x ) 1 / 3 f − 1 ( x ) = 5 9 ( x − 32 ) . f − 1 ( x ) = 5 9 ( x − 32 ) . Given the Fahrenheit temperature, x , x , this formula allows you to calculate the Celsius temperature. t ( d ) = d 50 , t ( d ) = d 50 , t ( 180 ) = 180 50 . t ( 180 ) = 180 50 . The time for the car to travel 180 miles is 3.6 hours. ## Review Exercises f ( − 3 ) = − 27 ; f ( − 3 ) = − 27 ; f ( 2 ) = − 2 ; f ( 2 ) = − 2 ; f ( − a ) = − 2 a 2 − 3 a ; f ( − a ) = − 2 a 2 − 3 a ; − f ( a ) = 2 a 2 − 3 a ; − f ( a ) = 2 a 2 − 3 a ; f ( a + h ) = − 2 a 2 + 3 a − 4 a h + 3 h − 2 h 2 f ( a + h ) = − 2 a 2 + 3 a − 4 a h + 3 h − 2 h 2 x = − 1.8 x = − 1.8 or or x = 1.8 or x = 1.8 − 64 + 80 a − 16 a 2 − 1 + a = − 16 a + 64 − 64 + 80 a − 16 a 2 − 1 + a = − 16 a + 64 ( − ∞ , − 2 ) ∪ ( − 2 , 6 ) ∪ ( 6 , ∞ ) ( − ∞ , − 2 ) ∪ ( − 2 , 6 ) ∪ ( 6 , ∞ ) increasing ( 2 , ∞ ) ; ( 2 , ∞ ) ; decreasing ( − ∞ , 2 ) ( − ∞ , 2 ) increasing ( − 3 , 1 ) ; ( − 3 , 1 ) ; constant ( − ∞ , − 3 ) ∪ ( 1 , ∞ ) ( − ∞ , − 3 ) ∪ ( 1 , ∞ ) local minimum ( − 2 , − 3 ) ; ( − 2 , − 3 ) ; local maximum ( 1 , 3 ) ( 1 , 3 ) ( − 1.8 , 10 ) ( − 1.8 , 10 ) ( f ∘ g ) ( x ) = 17 − 18 x ; ( g ∘ f ) ( x ) = − 7 − 18 x ( f ∘ g ) ( x ) = 17 − 18 x ; ( g ∘ f ) ( x ) = − 7 − 18 x ( f ∘ g ) ( x ) = 1 x + 2 ; ( g ∘ f ) ( x ) = 1 x + 2 ( f ∘ g ) ( x ) = 1 x + 2 ; ( g ∘ f ) ( x ) = 1 x + 2 ( f ∘ g ) ( x ) = 1 + x 1 + 4 x , x ≠ 0 , x ≠ − 1 4 ( f ∘ g ) ( x ) = 1 + x 1 + 4 x , x ≠ 0 , x ≠ − 1 4 ( f ∘ g ) ( x ) = 1 x , x > 0 ( f ∘ g ) ( x ) = 1 x , x > 0 sample: g ( x ) = 2 x − 1 3 x + 4 ; f ( x ) = x g ( x ) = 2 x − 1 3 x + 4 ; f ( x ) = x f ( x ) = | x − 3 | f ( x ) = | x − 3 | f ( x ) = 1 2 | x + 2 | + 1 f ( x ) = 1 2 | x + 2 | + 1 f ( x ) = − 3 | x − 3 | + 3 f ( x ) = − 3 | x − 3 | + 3 f − 1 ( x ) = x - 9 10 f − 1 ( x ) = x - 9 10 f − 1 ( x ) = x - 1 f − 1 ( x ) = x - 1 The function is one-to-one. ## Practice Test The relation is a function. The graph is a parabola and the graph fails the horizontal line test. 2 a 2 − a 2 a 2 − a − 2 ( a + b ) + 1 − 2 ( a + b ) + 1 f − 1 ( x ) = x + 5 3 f − 1 ( x ) = x + 5 3 ( − ∞ , − 1.1 ) and ( 1.1 , ∞ ) ( − ∞ , − 1.1 ) and ( 1.1 , ∞ ) ( 1.1 , − 0.9 ) ( 1.1 , − 0.9 ) f ( 2 ) = 2 f ( 2 ) = 2 f ( x ) = { | x | if x ≤ 2 3 if x > 2 f ( x ) = { | x | if x ≤ 2 3 if x > 2 x = 2 x = 2 f − 1 ( x ) = − x − 11 2 f − 1 ( x ) = − x − 11 2 As an Amazon Associate we earn from qualifying purchases. This book may not be used in the training of large language models or otherwise be ingested into large language models or generative AI offerings without OpenStax's permission. Want to cite, share, or modify this book? This book uses the Creative Commons Attribution License and you must attribute OpenStax. Access for free at https://openstax.org/books/college-algebra/pages/1-introduction-to-prerequisites • Authors: Jay Abramson • Publisher/website: OpenStax • Book title: College Algebra • Publication date: Feb 13, 2015 • Location: Houston, Texas • Book URL: https://openstax.org/books/college-algebra/pages/1-introduction-to-prerequisites • Section URL: https://openstax.org/books/college-algebra/pages/chapter-3 © Dec 8, 2021 OpenStax. Textbook content produced by OpenStax is licensed under a Creative Commons Attribution License . 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Read More Louisiana Department of Education is not affiliated to Lumos Learning. Louisiana department of education, was not involved in the production of, and does not endorse these products or this site. ## Chapter 9, Lesson 5: Exponential Functions • Extra Examples • Personal Tutor • Self-Check Quizzes The resource you requested requires you to enter a username and password below: Please read our Terms of Use and Privacy Notice before you explore our Web site. To report a technical problem with this Web site, please contact the site producer . #### IMAGES 1. Lesson 3 Problem Solving Practice Write Two Step Equations Answers 2. problem solving management theory 3. Algebra 3-4 Complex Numbers Worksheet 4. What Is Problem-Solving? Steps, Processes, Exercises to do it Right 5. three stages of problem solving according to traditional models 6. Problem Solving #### VIDEO 1. Chapter 3 Problem Solving (part 1) 2. 40 Days Challenge for the Board Students 3. 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Algebra 1 The Algebra 1 course, often taught in the 9th grade, covers Linear equations, inequalities, functions, and graphs; Systems of equations and inequalities; Extension of the concept of a function; Exponential models; and Quadratic equations, functions, and graphs. Khan Academy's Algebra 1 course is built to deliver a comprehensive, illuminating, engaging, and Common Core aligned experience! 4. PDF Chapter 3 Resource Masters ©Glencoe/McGraw-Hill iv Glencoe Geometry Teacher's Guide to Using the Chapter 3 Resource Masters The Fast FileChapter Resource system allows you to conveniently file the resources you use most often. The Chapter 3 Resource Mastersincludes the core materials needed for Chapter 3. These materials include worksheets, extensions, and assessment options. 5. Algebra 2 Common Core Chapter 3 Algebra 2 Common Core answers to Chapter 3 - Linear Systems - 3-1 Solving Systems Using Tables and Graphs - Practice and Problem-Solving Exercises - Page 138 7 including work step by step written by community members like you. Textbook Authors: Hall, Prentice, ISBN-10: 0133186024, ISBN-13: 978--13318-602-4, Publisher: Prentice Hall 6. Solving equations & inequalities Why we do the same thing to both sides: Variable on both sides. Intro to equations with variables on both sides. Equations with variables on both sides: 20-7x=6x-6. Equation with variables on both sides: fractions. Equation with the variable in the denominator. 7. Student Workbooks Chapter Resources Chapter Readiness Quiz Chapter Test Concepts in Motion Family Letters and Activities ... and Problem Solving, Course 3. Student Workbooks. Noteables Interactive Study Notebook (27931.0K) Skills Practice Workbook (5856.0K) Study Guide and Intervention and Practice Workbook (11412.0K) Word Problem Practice Workbook (4129.0K) Log ... 8. 3.6: Chapter 3 Exercises with Solutions Exercise. Draw a coordinate system on a sheet of graph paper for which the x- and y-axes both range from −10 to 10. a) Draw a line that contains the point (1, −2) and has slope 1/3. Label the line as (a). b) On the same coordinate system, draw a line that contains the point (0, 1) and has slope −3. Label it as (b). 9. Chapter 3 Review Exercises Find the percent increase. Answer. Exercise 26. Rowena's monthly gasoline bill dropped from83.75 last month to $56.95 this month. Find the percent decrease. Solve Simple Interest Applications. In the following exercises, solve. Exercise 27. Winston deposited$3,294 in a bank account with interest rate 2.6%.

Introduction to Systems of Equations and Inequalities; 7.1 Systems of Linear Equations: Two Variables; 7.2 Systems of Linear Equations: Three Variables; 7.3 Systems of Nonlinear Equations and Inequalities: Two Variables; 7.4 Partial Fractions; 7.5 Matrices and Matrix Operations; 7.6 Solving Systems with Gaussian Elimination; 7.7 Solving Systems with Inverses; 7.8 Solving Systems with Cramer's Rule

11. Algebra 1 Common Core

Chapter 3:Solving Inequalities. Page 161: Get Ready! Section 3-1: Inequalities and Their Graphs. Section 3-2: Solving Inequalities Using Addition and Subtraction. Section 3-3: Solving Inequalities Using Multiplication or Division. Section 3-4: Solving Multi-Step Inequalities. Page 193: Mid-Chapter Quiz. Section 3-5: Working with Sets.

12. Chapter 3, Lesson 5: Solving Two-Step Equations

Standardized Test Practice Vocabulary Review Lesson Resources Extra Examples Group Activity Cards ... Multilingual eGlossary Visual Vocabulary Cards Online Calculators Study to Go. Mathematics. Home > Chapter 3 > Lesson 5. North Carolina Math Connects: Concepts, Skills, and Problem Solving, Course 2. Chapter 3, Lesson 5: Solving Two-Step ...

13. PDF Skills Practice Workbook

Problem-Solving Investigation: Use a Venn Diagram. Use a Venn diagram to solve each problem. PHONE SERVICE Of the 5,750 residents of Homer, Alaska, 2,330 pay for landline phone service and 4,180 pay for cell phone service. One thousand seven hundred fifty pay for both landline and cell phone service.

14. Math Connects: Concepts, Skills, and Problem Solving Course 3

Title : Math Connects: Concepts, Skills, and Problem Solving Course 3 Publisher : Glencoe/McGraw-Hill Grade : 8 ISBN : 78740509 ISBN-13 : 9780078740503

15. Chapter 3 and 4 Notes

Chapter 3: Teaching Through Problem Solving Problem Solving Teaching FOR problem solving Teaching skills, then providing problems to practice those skills (explain- practice-apply) Teaching ABOUT problem solving Polya's four-step problem solving process (understand, devise a plan, carry out the plan, look back) Teaching THROUGH problem solving Teaching content through real context, problems ...

16. Math Connects: Concepts, Skills, and Problem Solving, Course 3

Math Connects: Concepts, Skills, and Problem Solving, Course 3. Click an item at the left to access links, activities, and more. Once your teacher has registered for the online student edition, he or she will give you the user name and password needed to view the book. Click here to access your eBook.

17. PDF Skills Practice Workbook

001_009_CRM01_881031. Use the four-step plan to solve each problem. 1. GEOGRAPHY. The president is going on a campaign trip to California, first. flying about 2,840 miles from Washington, D.C., to San Francisco and. then another 390 to Los Angeles before returning the 2,650 miles back to.

18. PDF Practice Workbook

world.The materials are organized by chapter and lesson, with one Practice worksheet for every lesson in Glencoe California Mathematics, Grade 7. Always keep your workbook handy. Along with your textbook, daily homework, and class notes, ... Practice A Plan for Problem Solving Toppings Price 1 $12.99 2$13.79 3 $14.59 4$15.39 7MR1.1, 6AF2.3

19. Chapter 9, Lesson 5: Exponential Functions

Problem Solving Handbook Cross-Curricular Projects Other Calculator Keystrokes Meet the Authors About the Cover Scavenger Hunt Recording Sheet Chapter Resources Chapter Readiness Quiz Chapter Test Concepts in Motion Real-World Careers California Standards Practice (STP) Vocabulary Review Lesson Resources Extra Examples Personal Tutor Self-Check ...