Maximization Transportation Problem

There are certain types of transportation problems where the objective function is to be maximized instead of being minimized.

These problems can be solved by converting the maximization problem into a minimization problem.

"Profit maximization is the single universal objective for most commercial organizations." -Vinay Chhabra & Manish Dewan

Example: Maximization Problem in Transportation

Surya Roshni Ltd. has three factories - X, Y, and Z. It supplies goods to four dealers spread all over the country. The production capacities of these factories are 200, 500 and 300 per month respectively.

Determine a suitable allocation to maximize the total net return.

Maximization transportation problem can be converted into minimization transportation problem by subtracting each transportation cost from maximum transportation cost.

Here, the maximum transportation cost is 25. So subtract each value from 25. The revised transportation problem is shown below.

An initial basic feasible solution is obtained by matrix minimum method and is shown in the final table.

Final table

Use Horizontal Scrollbar to View Full Table Calculation.

The maximum net return is

25 X 200 + 8 X 80 + 7 X 320 + 10 X 100 + 14 X 100 + 20 X 200 = 14280.

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Balanced and Unbalanced Transportation Problems

The two categories of transportation problems are balanced and unbalanced transportation problems . As we all know, a transportation problem is a type of Linear Programming Problem (LPP) in which items are carried from a set of sources to a set of destinations based on the supply and demand of the sources and destinations, with the goal of minimizing the total transportation cost. It is also known as the Hitchcock problem.

Introduction to Balanced and Unbalanced Transportation Problems

Balanced transportation problem.

The problem is considered to be a balanced transportation problem when both supplies and demands are equal.

Unbalanced Transportation Problem

Unbalanced transportation problem is defined as a situation in which supply and demand are not equal. A dummy row or a dummy column is added to this type of problem, depending on the necessity, to make it a balanced problem. The problem can then be addressed in the same way as the balanced problem.

Methods of Solving Transportation Problems

There are three ways for determining the initial basic feasible solution. They are

1. NorthWest Corner Cell Method.

2. Vogel’s Approximation Method (VAM).

3. Least Call Cell Method.

The following is the basic framework of the balanced transportation problem:

Basic Structure of Balanced Transportation Problem

The destinations D1, D2, D3, and D4 in the above table are where the products/goods will be transported from various sources O1, O2, O3, and O4. The supply from the source Oi is represented by S i . The demand for the destination Dj is d j . If a product is delivered from source Si to destination Dj, then the cost is called C ij .

Let us now explore the process of solving the balanced transportation problem using one of the ways known as the NorthWest Corner Method in this article.

Solving Balanced Transportation problem by Northwest Corner Method

Consider this scenario:

Balanced Transportation Problem -1

With three sources (O1, O2, and O3) and four destinations (D1, D2, D3, and D4), what is the best way to solve this problem? The supply for the sources O1, O2, and O3 are 300, 400, and 500, respectively. Demands for the destination D1, D2, D3, and D4 are 250, 350, 400, and 200, respectively.

The starting point for the North West Corner technique is (O1, D1), which is the table’s northwest corner. The cost of transportation is calculated for each value in the cell. As indicated in the diagram, compare the demand for column D1 with the supply from source O1 and assign a minimum of two to the cell (O1, D1).

Column D1’s demand has been met, hence the entire column will be canceled. The supply from the source O1 is still 300 – 250 = 50.

Balanced Transportation Problem - 2

Analyze the northwest corner, i.e. (O1, D2), of the remaining table, excluding column D1, and assign the lowest among the supply for the appropriate column and rows. Because the supply from O1 is 50 and the demand for D2 is 350, allocate 50 to the cell (O1, D2).

Now, row O1 is canceled because the supply from row O1 has been completed. Hence, the demand for Column D2 has become 350 – 50 = 50.

Balanced Transportation Problem - 3

The northwest corner cell in the remaining table is (O2, D2). The shortest supply from source O2 (400) and the demand for column D2 (300) is 300, thus putting 300 in the cell (O2, D2). Because the demand for column D2 has been met, the column can be deleted, and the remaining supply from source O2 is 400 – 300 = 100.

Balanced Transportation Problem - 4

Again, find the northwest corner of the table, i.e. (O2, D3), and compare the O2 supply (i.e. 100) to the D2 demand (i.e. 400) and assign the smaller (i.e. 100) to the cell (O2, D2). Row O2 has been canceled because the supply from O2 has been completed. Column D3 has a leftover demand of 400 – 100 = 300.

Balanced Transportation Problem -5

Continuing in the same manner, the final cell values will be:

Balanced Transportation Problem - 6

It should be observed that the demand for the relevant columns and rows is equal in the last remaining cell, which was cell (O3, D4). In this situation, the supply from O3 was 200, and the demand for D4 was 200, therefore this cell was assigned to it. Nothing was left for any row or column at the end.

To achieve the basic solution, multiply the allotted value by the respective cell value (i.e. the cost) and add them all together.

I.e., (250 × 3) + (50 × 1) + (300 × 6) + (100 × 5) + (300 × 3) + (200 × 2) = 4400.

Solving Unbalanced Transportation Problem

An unbalanced transportation problem is provided below. Because the sum of all the supplies, O1, O2, O3, and O4, does not equal the sum of all the demands, D1, D2, D3, D4, and D5, the situation is unbalanced.

Unbalanced Transportation Problem - 1

The idea of a dummy row or dummy column will be applied in this type of scenario. Because the supply is more than the demand in this situation, a fake demand column will be inserted, with a demand of (total supply – total demand), i.e. 117 – 95 = 22, as seen in the image below. A fake supply row would have been introduced if demand was greater than supply.

Unbalanced Transportation Problem - 2

Now this problem has been changed to a balanced transportation problem, and it can be addressed using any of the ways listed below to solve a balanced transportation problem, such as the northwest corner method mentioned earlier.

Frequently Asked Questions on Balanced and Unbalanced Transportation Problems

What is meant by balanced and unbalanced transportation problems.

The problem is referred to as a balanced transportation problem when both supplies and demands are equal. Unbalanced transportation is defined as a situation where supply and demand are not equal.

What is called a transportation problem?

The transportation problem is a type of Linear Programming Problem in which commodities are carried from a set of sources to a set of destinations while taking into account the supply and demand of the sources and destinations, respectively, in order to reduce the total cost of transportation.

What are the different methods to solve transportation problems?

The following are three approaches to solve the transportation issue:

  • NorthWest Corner Cell Method.
  • Least Call Cell Method.
  • Vogel’s Approximation Method (VAM).

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BCIS Fourth Semester

Transportation Problem, Data Analysis and Modeling || Bcis Notes

April 5, 2021 Ritik Bhujel DAM 0

Transportation Problem, Data Analysis and Modeling || Bcis Notes

Transportations Problems

1 Introduction: The transportation problem is concerned to determine the amount that should be shipped from each source to each destination to make the total transportation cost minimum and at the same time satisfying the supply limits and the demand requirements. The transportation problem is concerned with selecting routes to distribute the goods in the different destinations in order to minimize the total transportation cost or to maximize the total revenue of the problem by satisfying the requirements of the different destinations and supply quantities of different sources.

2  Formulation of transportation problems as a linear programming problem: The transportation problem is in the tabular form (matrix form) as shown

Where, there are ‘m’ sources S 1 , S 2 , ………, S m having a i (i=1,2,…..,m ) units of supplies or capacity respectively to be transported among ‘n’ destinations D 1 , D 2 , ………, D n  with b j ( j= 1,2,……..,n ) units of requirements respectively.

C ij be the cost of shipping one unit of the commodity from sources ‘i’ to destination ‘j’ and X ij denotes the number of units shipped per route from source ‘i’ to destination ‘j’.

Now, this transportation problem is formulated to minimize the total transportation cost as

Minimize Z = C 11 X 11 + C 12 X 12 +………+ C m n X m n

Z = C ij X ij

Subjected to constraints

Supply constraints

X 11 + X 12 +………+   X 1 n = a 1

X 21 + X 22 +………+   X 2 n = a 2

………………………………

X m1 + X m2 +………+   X m n = a m

Demand constraints

X 11 + X 21 +………+   X m1 = b 1

X 12 + X 22 +………+   X   m2 = b 2

X 1 n + X 2 n +………+   X m n = b n

X i j  0 , for all i and j .

3  Types of transportations problems: There are two types of transportation problems depending upon supply and demand.

  • Balanced transportation problem: If total supply equals total demand. Then problem is called a balanced transportation problem.
  • Unbalanced transportation problem: If total supply does not equal to total demands. Then problem is called an unbalanced transportation problem.

  Note: It should be noted that the transportation problem will be solved when we convert unbalanced transportation problem into balanced transportation problem.

4 Methods of converting unbalanced transportation problem into balanced transportation problem:

  • When demand exceeds supply. When total supply (a i ) is less than total demand (b j ), at that time, introduce a dummy source (dummy row) in the transportation table to make total supply equals to total demand. Here, in this dummy row, the unit cost of transporting from this source to any destination is set to zero.
  • When supply exceeds demand. When total supply (a i ) is greater than total demand ( bj ), at that time, introduce a dummy destination (dummy column) in the transportation table to make total demand equals to total supply. Here, in this dummy column, the unit cost of transporting from different sources to this dummy destination is set to zero.

5 Definition of some basic terms:

  • Source: It is the place of origin from which the goods or services are supplied to the different places of destinations.
  • Destination: It is the place of demand where the goods are required in certain finite quantities.
  • Occupied (basic)cells and non-occupied (non-basic) cells: Squares (cells) in the transportation table having positive allocation are called occupied cells, otherwise, called empty or non-occupied cells.
  • The feasible solution : A set of non-negative values X ij that satisfied the constraints of given T.P. is called a feasible solution to the transportation problem.
  • The basic feasible solution: A feasible solution that contains no more than (R+C-1) non-negative allocations is called a basic feasible solution, where ‘R’ is no. of rows and ‘C’ is the no. of columns in the transportation table.
  • Degeneracy: When the number of occupied cells (basic cells) of general T.P. is less than (R+C-1), Then it is called degeneracy in transportation problem, and the solution is called degeneracy basic feasible solution.
  • Non – degeneracy: when the number of occupied cells (basic cells) of general T.P. is exactly equal to (R+C-1), then it is called non-degeneracy in the transportation problem, and the solution is called non-degeneracy basic feasible solution.

6  Methods of obtaining the initial basic feasible solution of transportation problem:

  • Northwest corner method.
  • Least cost method Or Greedy Method.
  • Vogel’s approximation method or penalty method.

i)   Northwest corner method (NWCM):

In this method, the following systematic steps are used to obtain the initial basic feasible solutions.

  • Step 1 : Allocation starts with the cell (1,1) at the upper left ( northwest ) corner of the transportation table and allocates as much as a possible value equal to the minimum of first row values and first column values i.e. min ( a 1, b 1 )
  • (a) If the allocation made in step 1 is equal to the capacity of the first row (a 1 ), then move vertically down to the cell (2, 1) to fulfill the remaining demand of the first column. Here allocation is made according to step 1.
  • (b) If the allocation made in step 1 is equal to the demand of the first column (b 1 ), then move horizontally to the cell (1, 2) to finish the remaining capacity (sources) of the first row (source). Here allocation is made according to step 1.
  • (c) If allocation made in step 1 is equal to the capacity of the first source (a 1 ) and demand of first destination (b 1 ). Then move diagonally to the cell (2, 2). Here allocation is made according to step 1.
  • Step 3: continue the procedure step by step till an allocation is made in the southeast corner cell of the transportation table i.e. ( continue the above steps until all the capacity of all the sources are finishes and the demands of all the destinations are full filled).
  • Step 4: Calculate the total transportation cost, which is obtained as, at first multiply the allocated values with the corresponding unit cost for all occupied cells separately and then add all the multiple values which you obtained.

ii)  Least cost method (LCM) Or Greedy Method:

In this method, the following systematic steps are used to obtain the initial basic feasible solution.

  • Step 1: At first, select the cell having the smallest unit cost in the entire transportation table and allocate as much as possible value to this cell and then eliminate that row if the capacity of that row is finished or eliminate that column if the demand of that column (destination) is fulfilled.

Note 1: If both row (source) and column (destination) are satisfied simultaneously, then only one eliminates (crossed out)

Note 2: In case, the smallest unit cost is not unique, then select the cell where maximum allocation can be made.

  • Step 2: After the first step, again select the cell having the smallest unit cost out of uncrossed (non -eliminated) rows and columns. Then allocation is made to this cell according to step 1. Then eliminate that row and column in which either supply or demand is exhausted. This process should repeat until the entire available supply at various sources and demand at various destinations is satisfied.

The solution so obtained need not be non-degeneracy.

  • Step 3: Calculate the total transportation cost, which is obtained as, at first multiply the allocated values with the corresponding unit cost for all occupied cells separately and then add all the multiple values which you obtained.

iii)  Vogel’s approximation method:

In this method, the following systematic steps are used to obtain the initial basic feasible solution to the transportation problem.

  • Step 1: At first, calculate the difference between the smallest and next to smallest unit cost for each row (source) and column (destination). These differences are known as row and column opportunities (penalties) cost
  • Step 2: Select the row or column with the largest difference (opportunities cost). Then allocate as many units as possible to this row or column in the cell having the least unit cost.

Note: if there is a tie in the values of the opportunities cost. At that time, we select that row or column with minimum unit cost. Again if there is a tie in the unit cost, we select that cell of that row or column where maximum allocation can be made.

  • Step 3: After step 2, if the capacity of that row is finished, we eliminate that row. If the demand of that column is fulfilled, we eliminate that column. If the capacity of that row and demand of that column are satisfied simultaneously then only one of them is eliminated and in the remaining one, we assign zero supply or zero demand. Any row or column with zero supply or zero demand should not be used in computing future penalties (opportunities cost)
  • Step 4: Again, calculate the opportunity cost for the remaining rows and columns which are not eliminated.
  • Step 5: Repeat steps 2 to step 4 until the entire available supply at various sources (rows) and demand at various destinations (columns) are satisfied.
  • Step 6 : Calculate the total transportation cost, which is obtained as, at first multiply the allocated values with the corresponding unit cost for all occupied cells separately and then add all the multiple values which you obtained.

Note: Among the three methods, the total transportation cost obtained by Vogel’s approximation is the least so Vogel’s approximation is a more effective method for obtaining the initial basic feasible solution than other methods.

7  Maximization of transportation problems: Transportation problems may be of the maximization type, maximization may be profit or revenue or productions. To solve such type of maximization transportation problem, at first convert this maximization T.P. into minimization T.P. by subtracting each unit cost from the highest unit cost of maximization transportation problem. Then we will get the minimization transportation problem. Then we proceed with the same process, preceded in case of minimization T.P.

Note: during the calculation of the maximum value, we will consider the original table. In which we multiply allocated goods with corresponding unit cost separately and then add all the multiple values to obtain the maximum value.

You may also like this:  Method of Construction of Index Number 

  • Definition of some basic terms
  • Formulation of transportation problems as a linear programming problem
  • Methods of converting unbalanced transportation problem into balanced transportation problem
  • Methods of obtaining the initial basic feasible solution of transportation problem
  • Types of transportations problems

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Transportation Problem | Set 6 (MODI Method – UV Method)

There are two phases to solve the transportation problem. In the first phase, the initial basic feasible solution has to be found and the second phase involves optimization of the initial basic feasible solution that was obtained in the first phase. There are three methods for finding an initial basic feasible solution,

NorthWest Corner Method

  • Least Cost Cell Method
  • Vogel’s Approximation Method

This article will discuss how to optimize the initial basic feasible solution through an explained example. Consider the below transportation problem.

how to solve unbalanced transportation problem of maximization type

Check whether the problem is balanced or not. If the total sum of all the supply from sources

is equal to the total sum of all the demands for destinations

then the transportation problem is a balanced transportation problem.

how to solve unbalanced transportation problem of maximization type

If the problem is not unbalanced then the concept of a dummy row or a dummy column to transform the unbalanced problem to balanced can be followed as discussed in

Finding the initial basic feasible solution. Any of the three aforementioned methods can be used to find the initial basic feasible solution. Here,

will be used. And according to the NorthWest Corner Method this is the final initial basic feasible solution:

how to solve unbalanced transportation problem of maximization type

Now, the total cost of transportation will be

(200 * 3) + (50 * 1) + (250 * 6) + (100 * 5) + (250 * 3) + (150 * 2) = 3700

U-V method to optimize the initial basic feasible solution. The following is the initial basic feasible solution:

how to solve unbalanced transportation problem of maximization type

– For U-V method the values

have to be found for the rows and the columns respectively. As there are three rows so three

values have to be found i.e.

for the first row,

for the second row and

for the third row. Similarly, for four columns four

. Check the image below:

how to solve unbalanced transportation problem of maximization type

There is a separate formula to find

is the cost value only for the allocated cell. Read more about it

. Before applying the above formula we need to check whether

m + n – 1 is equal to the total number of allocated cells

or not where

is the total number of rows and

is the total number of columns. In this case m = 3, n = 4 and total number of allocated cells is 6 so m + n – 1 = 6. The case when m + n – 1 is not equal to the total number of allocated cells will be discussed in the later posts. Now to find the value for u and v we assign any of the three u or any of the four v as 0. Let we assign

in this case. Then using the above formula we will get

). Similarly, we have got the value for

so we get the value for

which implies

. From the value of

. See the image below:

how to solve unbalanced transportation problem of maximization type

Now, compute penalties using the formula

only for unallocated cells. We have two unallocated cells in the first row, two in the second row and two in the third row. Lets compute this one by one.

  • For C 13 , P 13 = 0 + 0 – 7 = -7 (here C 13 = 7 , u 1 = 0 and v 3 = 0 )
  • For C 14 , P 14 = 0 + (-1) -4 = -5
  • For C 21 , P 21 = 5 + 3 – 2 = 6
  • For C 24 , P 24 = 5 + (-1) – 9 = -5
  • For C 31 , P 31 = 3 + 3 – 8 = -2
  • For C 32 , P 32 = 3 + 1 – 3 = 1

If we get all the penalties value as zero or negative values that mean the optimality is reached and this answer is the final answer. But if we get any positive value means we need to proceed with the sum in the next step. Now find the maximum positive penalty. Here the maximum value is 6 which corresponds to

cell. Now this cell is new basic cell. This cell will also be included in the solution.

how to solve unbalanced transportation problem of maximization type

The rule for drawing closed-path or loop.

Starting from the new basic cell draw a closed-path in such a way that the right angle turn is done only at the allocated cell or at the new basic cell. See the below images:

how to solve unbalanced transportation problem of maximization type

Assign alternate plus-minus sign to all the cells with right angle turn (or the corner) in the loop with plus sign assigned at the new basic cell.

how to solve unbalanced transportation problem of maximization type

Consider the cells with a negative sign. Compare the allocated value (i.e. 200 and 250 in this case) and select the minimum (i.e. select 200 in this case). Now subtract 200 from the cells with a minus sign and add 200 to the cells with a plus sign. And draw a new iteration. The work of the loop is over and the new solution looks as shown below.

how to solve unbalanced transportation problem of maximization type

Check the total number of allocated cells is equal to (m + n – 1). Again find u values and v values using the formula

is the cost value only for allocated cell. Assign

then we get

. Similarly, we will get following values for

how to solve unbalanced transportation problem of maximization type

Find the penalties for all the unallocated cells using the formula

  • For C 11 , P 11 = 0 + (-3) – 3 = -6
  • For C 13 , P 13 = 0 + 0 – 7 = -7
  • For C 14 , P 14 = 0 + (-1) – 4 = -5
  • For C 31 , P 31 = 0 + (-3) – 8 = -11

There is one positive value i.e. 1 for

. Now this cell becomes new basic cell.

how to solve unbalanced transportation problem of maximization type

Now draw a loop starting from the new basic cell. Assign alternate plus and minus sign with new basic cell assigned as a plus sign.

how to solve unbalanced transportation problem of maximization type

Select the minimum value from allocated values to the cell with a minus sign. Subtract this value from the cell with a minus sign and add to the cell with a plus sign. Now the solution looks as shown in the image below:

how to solve unbalanced transportation problem of maximization type

Check if the total number of allocated cells is equal to (m + n – 1). Find u and v values as above.

how to solve unbalanced transportation problem of maximization type

Now again find the penalties for the unallocated cells as above.

  • For P 11 = 0 + (-2) – 3 = -5
  • For P 13 = 0 + 1 – 7 = -6
  • For P 14 = 0 + 0 – 4 = -4
  • For P 22 = 4 + 1 – 6 = -1
  • For P 24 = 4 + 0 – 9 = -5
  • For P 31 = 2 + (-2) – 8 = -8

All the penalty values are negative values. So the optimality is reached. Now, find the total cost i.e.

(250 * 1) + (200 * 2) + (150 * 5) + (50 * 3) + (200 * 3) + (150 * 2) = 2450

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how to solve unbalanced transportation problem of maximization type

  • Sova Pal 1 ,
  • Prasenjit Pramanik   ORCID: orcid.org/0000-0002-0957-8875 2 ,
  • Ajoy Kumar Maiti 3 &
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Here, a general methodology is proposed to formulate and solve any multidimensional balanced/unbalanced, constrained/unconstrained transportation problems(TP) in different environments(crisp/fuzzy/rough). To understand the general model easily, here, at first, a multi-item 5-dimensional fixed charge profit maximization TP under budget and time constraint is presented. A potential solution of the problem is coded as a permutation of the different cells of the allocation matrix. A general decoding rule is proposed to determine the actual allocation from this coded solution. A heuristic approach is applied on a set of randomly generated coded solution of the target problem to determine the marketing decision. Applying swap operations on the coded solutions, the perturbation rules of the heuristic Particle Swarm Optimization(PSO) are modified to solve the problem. In a particular case, the problem is analysed as a bi-criteria decision making problem with the maximization of the total profit as well as the minimization of the total shipment time under a budget constraint. The bi-criteria TP is formulated as a single objective optimisation problem using a proposed rule and the same heuristic is run for a finite number of times to determine the pareto optimal front. To formulate the problem in the fuzzy(rough) environment an approach is proposed using credibility(trust) measure of fuzzy(rough) events. Proper fuzzy(rough) simulation algorithms are also proposed to solve the problem for any type of fuzzy(rough) estimation. Using this approach no crisp equivalent of any imprecise parameters is used for the marketing decision. Due the unavailability of the test data in the literature, different hypothetical data sets are used for the illustration of the models.

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Department of Applied Mathematics with Oceanology and Computer Programming, Vidyasagar University, Paschim-Medinipur, Midnapore, West Bengal, 721102, India

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5-dimensional multi item TP under different constraints in both precise and imprecise environments: Discussion, mathematical formulation, solution methodology, numerical illustration. Multi-dimensional multi item TP: theoretical discussion, mathematical formulation, solution methodology. Fuzzy and Rough Simulation: Algorithm developed and used. Soft Computing technique: Swap sequence based PSO.

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Pal, S., Pramanik, P., Maiti, A.K. et al. Multi-dimensional transportation problems in multiple environments: a simulation based heuristic approach. Soft Comput 27 , 11603–11628 (2023). https://doi.org/10.1007/s00500-023-08204-x

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how to solve unbalanced transportation problem of maximization type

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COMMENTS

  1. Maximization Transportation Problem

    Solution. Maximization transportation problem can be converted into minimization transportation problem by subtracting each transportation cost from maximum transportation cost. Here, the maximum transportation cost is 25. So subtract each value from 25. The revised transportation problem is shown below. Table 1. Factory. Dealer.

  2. Balanced and Unbalanced Transportation Problems

    Unbalanced Transportation Problem. Unbalanced transportation problem is defined as a situation in which supply and demand are not equal. A dummy row or a dummy column is added to this type of problem, depending on the necessity, to make it a balanced problem. The problem can then be addressed in the same way as the balanced problem.

  3. Transportation Problem

    An introduction to the transportation problem has been discussed in. this. article. In this article, the method to solve the unbalanced transportation problem will be discussed. Below transportation problem is an unbalanced transportation problem. The problem is unbalanced because the sum of all the supplies i.e. O1. O2.

  4. PDF Method for Solving Unbalanced Transportation Problems Using Standard

    the unbalanced transportation problem is ˆ I = E = 1 = ˆ > F J + 1 F (or) :or ;ˆ = E = ˆ J > F F=1 I + 1 F.That is ,the total supply must equal to demand. 4. Un Balanced Transportation Table (TT) Unbalanced transportation Table: (Excess availability ie ˆ = E > ˆ > F) Figure 1: Transpotation Table of Unbalanced Transportation Problem

  5. Operation Research: Transportation Problem Maximization

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  7. PART-7 MAXIMIZATION IN TRANSPORTATION PROBLEM

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  8. PDF UNBALANCED TRANSPORTATION PROBLEM

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    A transportation problem is a special type of linear programming problems and typically involves situations where goods are required to be transferred from some sources, or plants, to some destinations, or markets, at a minimum cost. Although such problems can be formulated and solved as linear programming problems, obtaining such solution is

  10. PDF Optimal Solution of Transportation Problem Based on Revised

    IV. A NEW APPROACH FOR SOLVING TRANSPORTATION PROBLEM This section presents Revised Distribution Method to solve the Maximization type transportation problem which is different from the preceding method. Revised Distribution method is also easy to apply both type of balanced [1] and unbalanced transportation problem [2]. . Step 1.

  11. Transportation, Transshipment, and Assignment Problems

    Use the transportation method to solve problems with Excel. Solve maximization transportation problems, unbalanced problems, and problems with prohibited routes. Solve aggregate planning problems using the transportation model. Formulate a transshipment problem as a linear programming model. Solve transshipment problems with Excel. Formulate an ...

  12. optimize Transportation problem

    To solve a transportation problem, the following information must be given: m= The number of sources. n= The number of destinations. The total quantity available at each source. The total quantity required at each destination. The cost of transportation of one unit of the commodity from each source to each destination.

  13. Transportation Problem, Data Analysis and Modeling || Bcis Notes

    Unbalanced transportation problem: If total supply does not equal to total demands. Then problem is called an unbalanced transportation problem. ... To solve such type of maximization transportation problem, at first convert this maximization T.P. into minimization T.P. by subtracting each unit cost from the highest unit cost of maximization ...

  14. Problem of Maximization

    In this video, we will learn how to solve the problems of maximization in transportation problem.Test of Optimality Part-1 video link :https://youtu.be/VAWrS...

  15. Transportation Problem

    then the transportation problem is a balanced transportation problem. Note: If the problem is not unbalanced then the concept of a dummy row or a dummy column to transform the unbalanced problem to balanced can be followed as discussed in . this. article. Step 2: Finding the initial basic feasible solution.

  16. PDF Maximization Transportation Problem

    These kinds of problems can be solved by converting the maximization problem into minimization problem. The conversion of maximization into minimization is done by subtracting the unit costs from the highest unit cost of the table. The maximization of transportation problem is illustrated with the following Example. Example:

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    The method herewith proposes to solve the maximization and minimization type of transportation problems and all its kinds. This research effectively and efficiently deduces the ... the Unbalanced Transportation Problem", Applied Mathematical Letter, Vol.3, No.2, pp. 9-11, 1980. 8. Pandian, P. and Anuradha, D. "A New Approach for solving bi-

  18. PDF Procedure for Solving Unbalanced Fuzzy Transportation Problem for

    Since the given problem is a maximization type, first convert into this into a minimization problem by subtracting the cost elements (entries or c ij) from the highest cost element (c ij = 9.6)in the given transportation problem. This problem is unbalanced fuzzy transportation problem then the problem convert to balanced fuzzy transportation

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    This video describes the solution for assignment question(Unbalanced maximization transportation problem)given.

  20. New Technique for Finding the Maximization to Transportation Problems

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  21. Multi-dimensional transportation problems in multiple ...

    Yang L, Liu L (2007) Fuzzy fixed charge solid transportation problem and algorithm. Appl Soft Comput 7:879-889. Article Google Scholar Yang L, Yuan F (2007) A bi-criteria solid transportation problem with fixed charge under stochastic environment. Appl Math Model 31:2668-2683

  22. Solve transportation problem using vogel's approximation method

    Find initial basic feasible solution for given problem by using. (a) North-West corner method. (b) Least cost method. (c) Vogel's approximation method. (d) obtain an optimal solution by MODI method. if the object is to minimize the total transportation cost. 2. Find an initial basic feasible solution for given transportation problem by using.